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The efficiency of a thermodynamic cycle cannot be infinite since it
- a)violates the I law of thermodynamics
- b)violates the II law of thermodynamics
- c)violates the III law of thermodynamics
- d)rejects no heat
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
The efficiency of a thermodynamic cycle cannot be infinite since ita)v...
The Second Law of Thermodynamics is violated when the efficiency of a thermodynamic cycle becomes infinite. This is because the Second Law states that it is impossible to create a perfect heat engine that converts all of the heat energy supplied to it into work without any waste heat.
Explanation:
The Second Law of Thermodynamics states that the total entropy of a closed system always increases over time. Entropy can be thought of as a measure of the disorder or randomness of a system. The Second Law also states that it is impossible to create a perfect heat engine that converts all of the heat energy supplied to it into work without any waste heat. This means that some of the heat energy will always be lost as waste heat to the environment.
The efficiency of a thermodynamic cycle is defined as the ratio of the work output of the cycle to the heat input. The maximum possible efficiency of a heat engine is given by the Carnot efficiency, which depends only on the temperatures of the hot and cold reservoirs. The Carnot efficiency can be expressed as:
Efficiency = (Th - Tc)/Th
where Th is the absolute temperature of the hot reservoir and Tc is the absolute temperature of the cold reservoir.
The efficiency of a real heat engine is always less than the Carnot efficiency due to various sources of inefficiency such as friction, heat loss to the environment, and imperfect combustion. However, the efficiency cannot be greater than the Carnot efficiency since this would violate the Second Law by implying that all of the heat energy supplied to the engine is converted into work without any waste heat.
Therefore, the efficiency of a thermodynamic cycle cannot be infinite since this would imply that all of the heat energy supplied to the engine is converted into work without any waste heat, which violates the Second Law of Thermodynamics.
Explanation:
The Second Law of Thermodynamics states that the total entropy of a closed system always increases over time. Entropy can be thought of as a measure of the disorder or randomness of a system. The Second Law also states that it is impossible to create a perfect heat engine that converts all of the heat energy supplied to it into work without any waste heat. This means that some of the heat energy will always be lost as waste heat to the environment.
The efficiency of a thermodynamic cycle is defined as the ratio of the work output of the cycle to the heat input. The maximum possible efficiency of a heat engine is given by the Carnot efficiency, which depends only on the temperatures of the hot and cold reservoirs. The Carnot efficiency can be expressed as:
Efficiency = (Th - Tc)/Th
where Th is the absolute temperature of the hot reservoir and Tc is the absolute temperature of the cold reservoir.
The efficiency of a real heat engine is always less than the Carnot efficiency due to various sources of inefficiency such as friction, heat loss to the environment, and imperfect combustion. However, the efficiency cannot be greater than the Carnot efficiency since this would violate the Second Law by implying that all of the heat energy supplied to the engine is converted into work without any waste heat.
Therefore, the efficiency of a thermodynamic cycle cannot be infinite since this would imply that all of the heat energy supplied to the engine is converted into work without any waste heat, which violates the Second Law of Thermodynamics.
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Community Answer
The efficiency of a thermodynamic cycle cannot be infinite since ita)v...
First law of thermodynamics as PMM1 violate it.
PMM1 machine cannot be designed which produces continuous work output with consuming energy.
Efficiency of PMM1 =WORK/ ZERO INPUT
= INFINITY
PMM1 machine cannot be designed which produces continuous work output with consuming energy.
Efficiency of PMM1 =WORK/ ZERO INPUT
= INFINITY
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The efficiency of a thermodynamic cycle cannot be infinite since ita)violates the I law of thermodynamicsb)violates the II law of thermodynamicsc)violates the III law of thermodynamicsd)rejects no heatCorrect answer is option 'B'. Can you explain this answer?
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