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15 ml of 0.02 normality of NaOH solution is mixed with 10 ml of 0.03 normality of other NaOH solution. Calculate resultant pH.
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15 ml of 0.02 normality of NaOH solution is mixed with 10 ml of 0.03 n...
**Calculating the Resultant pH**
To calculate the resultant pH of the solution, we need to determine the concentration of hydroxide ions (OH-) in the final mixture. This can be achieved by considering the dilution and the addition of the two NaOH solutions.
**Step 1: Determine the Moles of NaOH in each Solution**
To calculate the moles of NaOH, we can use the formula:
Moles = Normality × Volume (in liters)
For the first solution:
Moles of NaOH = 0.02 N × 0.015 L = 0.0003 moles
For the second solution:
Moles of NaOH = 0.03 N × 0.01 L = 0.0003 moles
**Step 2: Determine the Total Moles of NaOH**
To find the total moles of NaOH in the final mixture, we add the moles from both solutions:
Total moles of NaOH = 0.0003 moles + 0.0003 moles = 0.0006 moles
**Step 3: Determine the Total Volume of the Mixture**
To find the total volume of the mixture, we add the volumes of both solutions:
Total volume = 15 mL + 10 mL = 25 mL = 0.025 L
**Step 4: Calculate the Concentration of NaOH in the Final Mixture**
Concentration = Moles / Volume
Concentration of NaOH = 0.0006 moles / 0.025 L = 0.024 M
**Step 5: Calculate the Concentration of Hydroxide Ions (OH-)**
Since NaOH dissociates in water to form one hydroxide ion for every sodium hydroxide molecule, the concentration of hydroxide ions is the same as the concentration of NaOH:
Concentration of OH- = 0.024 M
**Step 6: Calculate the pOH**
pOH is defined as the negative logarithm of the hydroxide ion concentration:
pOH = -log[OH-] = -log(0.024) ≈ 1.62
**Step 7: Calculate the pH**
The pH can be determined using the formula:
pH = 14 - pOH ≈ 14 - 1.62 ≈ 12.38
Therefore, the resultant pH of the solution is approximately 12.38.
**Explanation**
The resultant pH of the mixture is calculated by finding the concentration of hydroxide ions, which is determined by combining the concentrations of NaOH from both solutions. The moles of NaOH in each solution are calculated using the given normality and volume. By adding the moles from both solutions, we find the total moles of NaOH in the mixture. The total volume is obtained by adding the volumes of both solutions. Dividing the total moles by the total volume gives the concentration of NaOH in the final mixture. Since NaOH dissociates to form one hydroxide ion for every molecule, the concentration of hydroxide ions is the same as the concentration of NaOH. The pOH is calculated by taking the negative logarithm of the hydroxide ion concentration. Finally, the pH is determined by subtracting the pOH from 14.
To calculate the resultant pH of the solution, we need to determine the concentration of hydroxide ions (OH-) in the final mixture. This can be achieved by considering the dilution and the addition of the two NaOH solutions.
**Step 1: Determine the Moles of NaOH in each Solution**
To calculate the moles of NaOH, we can use the formula:
Moles = Normality × Volume (in liters)
For the first solution:
Moles of NaOH = 0.02 N × 0.015 L = 0.0003 moles
For the second solution:
Moles of NaOH = 0.03 N × 0.01 L = 0.0003 moles
**Step 2: Determine the Total Moles of NaOH**
To find the total moles of NaOH in the final mixture, we add the moles from both solutions:
Total moles of NaOH = 0.0003 moles + 0.0003 moles = 0.0006 moles
**Step 3: Determine the Total Volume of the Mixture**
To find the total volume of the mixture, we add the volumes of both solutions:
Total volume = 15 mL + 10 mL = 25 mL = 0.025 L
**Step 4: Calculate the Concentration of NaOH in the Final Mixture**
Concentration = Moles / Volume
Concentration of NaOH = 0.0006 moles / 0.025 L = 0.024 M
**Step 5: Calculate the Concentration of Hydroxide Ions (OH-)**
Since NaOH dissociates in water to form one hydroxide ion for every sodium hydroxide molecule, the concentration of hydroxide ions is the same as the concentration of NaOH:
Concentration of OH- = 0.024 M
**Step 6: Calculate the pOH**
pOH is defined as the negative logarithm of the hydroxide ion concentration:
pOH = -log[OH-] = -log(0.024) ≈ 1.62
**Step 7: Calculate the pH**
The pH can be determined using the formula:
pH = 14 - pOH ≈ 14 - 1.62 ≈ 12.38
Therefore, the resultant pH of the solution is approximately 12.38.
**Explanation**
The resultant pH of the mixture is calculated by finding the concentration of hydroxide ions, which is determined by combining the concentrations of NaOH from both solutions. The moles of NaOH in each solution are calculated using the given normality and volume. By adding the moles from both solutions, we find the total moles of NaOH in the mixture. The total volume is obtained by adding the volumes of both solutions. Dividing the total moles by the total volume gives the concentration of NaOH in the final mixture. Since NaOH dissociates to form one hydroxide ion for every molecule, the concentration of hydroxide ions is the same as the concentration of NaOH. The pOH is calculated by taking the negative logarithm of the hydroxide ion concentration. Finally, the pH is determined by subtracting the pOH from 14.
Community Answer
15 ml of 0.02 normality of NaOH solution is mixed with 10 ml of 0.03 n...
0.024
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15 ml of 0.02 normality of NaOH solution is mixed with 10 ml of 0.03 normality of other NaOH solution. Calculate resultant pH.
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15 ml of 0.02 normality of NaOH solution is mixed with 10 ml of 0.03 normality of other NaOH solution. Calculate resultant pH. for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 15 ml of 0.02 normality of NaOH solution is mixed with 10 ml of 0.03 normality of other NaOH solution. Calculate resultant pH. covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 15 ml of 0.02 normality of NaOH solution is mixed with 10 ml of 0.03 normality of other NaOH solution. Calculate resultant pH..
15 ml of 0.02 normality of NaOH solution is mixed with 10 ml of 0.03 normality of other NaOH solution. Calculate resultant pH. for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 15 ml of 0.02 normality of NaOH solution is mixed with 10 ml of 0.03 normality of other NaOH solution. Calculate resultant pH. covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 15 ml of 0.02 normality of NaOH solution is mixed with 10 ml of 0.03 normality of other NaOH solution. Calculate resultant pH..
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