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From a uniform wire, two circular loops are made i) P of radius 'r' and ii)Q of radius nr. If the moment of inertia of Q about an axis passing through its centre and perpendicular to its plane is 8 times that of P about a similar axis, the value of 'n' is (diameter of the wire is very much smaller than r or nr)
  • a)
    8
  • b)
    6
  • c)
    4
  • d)
    2
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
From a uniform wire, two circular loops are made i) P of radius r and ...
Given: Two circular loops of radius r and nr are made from a uniform wire. The moment of inertia of Q about an axis passing through its centre and perpendicular to its plane is 8 times that of P about a similar axis.

To find: The value of n.

Solution:
Let the moment of inertia of P about its axis passing through its centre and perpendicular to its plane be I. Then, the moment of inertia of Q about its axis passing through its centre and perpendicular to its plane will be:

IQ = mr² + mr² + mr² + ...... n times
= mn(r/n)²
= m(r²/n)

Given, IQ = 8I

So, m(r²/n) = 8I
or, m(r/n)² = 8I/m
or, (r/n)² = 8I/m * 1/m
or, (r/n)² = 8I/m²

We know that the diameter of the wire is very much smaller than r or nr. So, we can assume that the wire is thin and we can use the formula for moment of inertia of a thin circular ring:

I = mR²
where m is the mass of the ring and R is the radius of the ring.

For the loop P, mass = M and radius = r.
So, IP = M*r²

For the loop Q, mass = M and radius = nr.
So, IQ = M*(nr)²

Given, IQ = 8IP
or, M*(nr)² = 8M*r²
or, (nr)² = 8r²
or, n² = 8

Therefore, n = 2 (since n cannot be negative).

Answer: The value of n is 2.
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From a uniform wire, two circular loops are made i) P of radius r and ii)Q of radius nr. If the moment of inertia of Q about an axis passing through its centre and perpendicular to its plane is 8 times that of P about a similar axis, the value of n is (diameter of the wire is very much smaller than r or nr)a)8b)6c)4d)2Correct answer is option 'D'. Can you explain this answer?
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