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A motor shaft consists of a steel tube 30 mm external diameter and 3 mm thick. The engine develops 10 kW at 2000 r.p.m. What will be the maximum stress in the tube, when the power is transmitted through 4 : 1 gearing?
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A motor shaft consists of a steel tube 30 mm external diameter and 3 m...
Problem Statement: Calculate the maximum stress in a motor shaft consisting of a steel tube with 30 mm external diameter and 3 mm thickness, when the engine develops 10 kW at 2000 r.p.m. and the power is transmitted through 4 : 1 gearing.

Solution:

  • Calculate torque: Torque = (Power × 60) / (2π × speed) = (10,000 × 60) / (2π × 2000) = 477.46 Nm

  • Calculate equivalent torque: Equivalent torque = Torque × Gear Ratio = 477.46 × 4 = 1909.84 Nm

  • Calculate maximum bending moment: Maximum bending moment = Equivalent torque × (Diameter / 2) = 1909.84 × (30 / 2) = 28647.6 Nmm

  • Calculate maximum stress: Maximum stress = (32 × Maximum bending moment) / (π × Diameter^3 × Thickness) = (32 × 28647.6) / (π × 30^3 × 3) = 49.31 MPa



Therefore, the maximum stress in the motor shaft is 49.31 MPa. The stress is within the permissible limit for steel, which is around 200 MPa. The steel tube can withstand the transmitted power without any deformation.
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A motor shaft consists of a steel tube 30 mm external diameter and 3 mm thick. The engine develops 10 kW at 2000 r.p.m. What will be the maximum stress in the tube, when the power is transmitted through 4 : 1 gearing?
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