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A ball rolling up an incline covers 36 metres during the first second, 32 metres during the second, 28 meters during the next and so on. How much distance will it travel during the 8th second?
- a)8 metres
- b)6 metres
- c)7 metres
- d)9 metres
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A ball rolling up an incline covers 36 metres during the first second...
Distance covered during the 1st second = 36 m
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Distance covered during the 2nd second = 32 m
Distance covered during the 3rd second = 28 m.
The distance covered form an A.P.
= 36 + 32 + 28 .... in which
a = 38, d = -4
∴ Distance covered in 8th second
= 8th term of the A.P.
= a + 7d = 36 + 7 (-4)
= 38 - 28 = 8 metres.
Most Upvoted Answer
A ball rolling up an incline covers 36 metres during the first second...
Given:
- The ball covers 36 meters during the first second.
- The ball covers 32 meters during the second second.
- The pattern continues with the ball covering 4 meters less in distance each second.
To find:
- The distance covered by the ball during the 8th second.
Solution:
To solve this problem, we can observe that the distance covered by the ball decreases by 4 meters each second. This means that the ball covers 36 meters in the first second, 32 meters in the second second, 28 meters in the third second, and so on.
We can represent this pattern as an arithmetic sequence, where the first term (a) is 36 and the common difference (d) is -4.
To find the distance covered by the ball during the 8th second, we can use the formula for the nth term of an arithmetic sequence:
a + (n-1)d
Substituting the values, we have:
a + (8-1)d = 36 + (8-1)(-4) = 36 + 7(-4) = 36 - 28 = 8 meters
Therefore, the distance covered by the ball during the 8th second is 8 meters.
Answer:
The ball will travel 8 meters during the 8th second.
- The ball covers 36 meters during the first second.
- The ball covers 32 meters during the second second.
- The pattern continues with the ball covering 4 meters less in distance each second.
To find:
- The distance covered by the ball during the 8th second.
Solution:
To solve this problem, we can observe that the distance covered by the ball decreases by 4 meters each second. This means that the ball covers 36 meters in the first second, 32 meters in the second second, 28 meters in the third second, and so on.
We can represent this pattern as an arithmetic sequence, where the first term (a) is 36 and the common difference (d) is -4.
To find the distance covered by the ball during the 8th second, we can use the formula for the nth term of an arithmetic sequence:
a + (n-1)d
Substituting the values, we have:
a + (8-1)d = 36 + (8-1)(-4) = 36 + 7(-4) = 36 - 28 = 8 meters
Therefore, the distance covered by the ball during the 8th second is 8 meters.
Answer:
The ball will travel 8 meters during the 8th second.
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A ball rolling up an incline covers 36 metres during the first second, 32 metres during the second, 28 meters during the next and so on. How much distance will it travel during the 8th second?a)8 metresb)6 metresc)7 metresd)9 metresCorrect answer is option 'A'. Can you explain this answer?
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A ball rolling up an incline covers 36 metres during the first second, 32 metres during the second, 28 meters during the next and so on. How much distance will it travel during the 8th second?a)8 metresb)6 metresc)7 metresd)9 metresCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A ball rolling up an incline covers 36 metres during the first second, 32 metres during the second, 28 meters during the next and so on. How much distance will it travel during the 8th second?a)8 metresb)6 metresc)7 metresd)9 metresCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball rolling up an incline covers 36 metres during the first second, 32 metres during the second, 28 meters during the next and so on. How much distance will it travel during the 8th second?a)8 metresb)6 metresc)7 metresd)9 metresCorrect answer is option 'A'. Can you explain this answer?.
A ball rolling up an incline covers 36 metres during the first second, 32 metres during the second, 28 meters during the next and so on. How much distance will it travel during the 8th second?a)8 metresb)6 metresc)7 metresd)9 metresCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A ball rolling up an incline covers 36 metres during the first second, 32 metres during the second, 28 meters during the next and so on. How much distance will it travel during the 8th second?a)8 metresb)6 metresc)7 metresd)9 metresCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball rolling up an incline covers 36 metres during the first second, 32 metres during the second, 28 meters during the next and so on. How much distance will it travel during the 8th second?a)8 metresb)6 metresc)7 metresd)9 metresCorrect answer is option 'A'. Can you explain this answer?.
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