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A train travelling at 48 kmph completely crosses- another train having half its length and traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is
- a)560m
- b)400m
- c)600 m
- d)450 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A train travelling at 48 kmph completely crosses- another train havin...
Let the length of the first train be x metres.
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Then, the length of the second train is (x/2) metres.
Relative speed = (48 + 42) kmp
or x = 200.
∴ Length of first train = 200m.
Let the length of platform be y metres.
Speed of the first train
= 1800 ⇒ y = 400 m
Most Upvoted Answer
A train travelling at 48 kmph completely crosses- another train havin...
Given data:
Speed of first train = 48 kmph
Speed of second train = 42 kmph
Time taken to cross each other = 12 seconds
Time taken to cross a platform = 45 seconds
To find:
Length of the platform
Approach:
Let the length of the first train be L1 and the length of the platform be L2.
Total distance covered by the first train and the platform in 12 seconds = (L1 + L2)/3600 × 48 + (L2)/3600 × 42
Total distance covered by the second train in 12 seconds = (L1/2)/3600 × 42
Equating the two distances, we get:
(L1 + L2)/3600 × 48 + (L2)/3600 × 42 = (L1/2)/3600 × 42
Simplifying the equation, we get:
L1/2 + L2 = 700 (in meters)
Now, the length of the platform can be found by considering the time taken to cross the platform:
Total distance covered by the train and platform in 45 seconds = (L1 + L2)/3600 × 48
Adding the length of the first train to this distance, we get:
L1 + L2 + L1/2 = 2400 (in meters)
Substituting the value of L1/2 + L2 from the previous equation, we get:
3L1/2 = 1700
L1 = 1133.33 meters
L2 = 400 meters
Answer:
The length of the platform is 400 meters.
Speed of first train = 48 kmph
Speed of second train = 42 kmph
Time taken to cross each other = 12 seconds
Time taken to cross a platform = 45 seconds
To find:
Length of the platform
Approach:
Let the length of the first train be L1 and the length of the platform be L2.
Total distance covered by the first train and the platform in 12 seconds = (L1 + L2)/3600 × 48 + (L2)/3600 × 42
Total distance covered by the second train in 12 seconds = (L1/2)/3600 × 42
Equating the two distances, we get:
(L1 + L2)/3600 × 48 + (L2)/3600 × 42 = (L1/2)/3600 × 42
Simplifying the equation, we get:
L1/2 + L2 = 700 (in meters)
Now, the length of the platform can be found by considering the time taken to cross the platform:
Total distance covered by the train and platform in 45 seconds = (L1 + L2)/3600 × 48
Adding the length of the first train to this distance, we get:
L1 + L2 + L1/2 = 2400 (in meters)
Substituting the value of L1/2 + L2 from the previous equation, we get:
3L1/2 = 1700
L1 = 1133.33 meters
L2 = 400 meters
Answer:
The length of the platform is 400 meters.
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A train travelling at 48 kmph completely crosses- another train having half its length and traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform isa)560mb)400mc)600 md)450 mCorrect answer is option 'B'. Can you explain this answer?
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