12.bA three phase fully controlled charges a battery from a supplied w...
Introduction:The given problem is related to a three-phase fully controlled rectifier circuit that charges a battery from a supplied voltage of 230 V, 50 Hz. The battery has an EMF of 200 V and an internal resistance of 0.5 Ω. The charging current is constant at 20 A due to the inductance connected in series with the battery. The task is to find the firing angle delay and supply power factor for the given circuit. Additionally, it is required to determine the firing angle delay if power flows from the DC source to the AC load.
Firing Angle Delay and Supply Power Factor:The circuit diagram of the three-phase fully controlled rectifier is shown below:
The firing angle delay of the circuit is given by the formula:
α = cos⁻¹[(Vd + Vr)/(√3 Vm)]
Where, Vd is the voltage drop across the diode, Vr is the voltage drop across the resistance, Vm is the maximum value of the supply voltage, and α is the firing angle delay.
In this case, the charging current is constant at 20 A due to the inductance connected in series with the battery. Therefore, the voltage drop across the resistance is Vr = IR = 20 x 0.5 = 10 V.
The voltage drop across the diode can be calculated as:
Vd = Vm√(3)/(π)sin(α)
Substituting the values, we get:
Vd = 230√(3)/(π)sin(α)
The power factor of the circuit can be calculated as:
PF = cos(α)
Substituting the values, we get:
PF = cos(cos⁻¹[(10 + Vr)/(√3 x 230)]) = 0.38
Therefore, the firing angle delay for the given circuit is α = 41.5° and the supply power factor is 0.38.
Firing Angle Delay for Power Flow from DC Source to AC Load:If power flows from the DC source to the AC load, the circuit becomes an inverter. The circuit diagram for the same is shown below:
The firing angle delay for power flow from the DC source to the AC load can be calculated using the formula:
α = cos⁻¹[(Vd - Vr)/(√3 Vm)]
Where, Vd is the voltage drop across the diode, Vr is the voltage drop across the resistance, Vm is the maximum value of the supply voltage, and α is the firing angle delay.
In this case, the voltage drop across the resistance is Vr = IR = 20 x 0.5 = 10 V.
The voltage drop across the diode can be calculated as:
Vd = Vm√(3)/(π)sin(π - α)
Substituting the values, we get:
Vd = 230√(3)/(π)