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A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?
- a)On AD at a distance of 30 m from A
- b)On BC at a distance of 10 m from B
- c)On AD at a distance of 30 m from D
- d)On BC at a distance of 10 m from C
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A square field ABCD of side 90 m is so located that its diagonal AC i...
Clearly, the arrangement is as shown in the adjoining diagram.
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It is given that Ram speed = 8 m/s.
Thames’s speed = 10 m/s
It Is clearly visible from the above figure that to meet for the first time, they have to cover a distance of 270 m i.e. three arms length of the field.
BA + AD + CD = 90 + 90 + 90 = 270 m
Since they are running in clockwise and anticlockwise direction respectively, they have to cover a di tance of 360 m (i.e. 4 arm's length of the field) for their second meeting from the first meeting point.
Thus, total distance to be covered for their second meeting = 270 + 360 = 630 m
Time required = 630/(8+10) = 630/18 = 35 seconds
Distance covered by Ram in clockwise direction In 35 seconds = 35 x 8 = 280 m
Distance covered by Thames in anticlockwise direction In 35 seconds = 35 x 10 = 350 m
Thus, Ram and Thames will meet on BC at a point 10 m from C and 80 m from B.
Most Upvoted Answer
A square field ABCD of side 90 m is so located that its diagonal AC i...
Problem Statement:
Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s. Where shall they cross each other the second time?
Given:
Square field ABCD of side 90 m, diagonal AC is from north to south, corner B is to the west of D.
Approach:
We need to find the point where Muong and Thames will cross each other for the second time. To find that point, we need to first find the time taken by each person to reach the first intersection point (say E), and then calculate the time taken by them to reach the second intersection point.
Solution:
Let E be the point where they cross each other for the first time.
Let F be the point where Muong meets AC.
Let G be the point where Thames meets AC.
Let AB be the X-axis and BC be the Y-axis.
Let the origin be at point B.
Time taken by Muong to reach E:
Distance traveled by Muong = Length of side AB + Distance of point F from E
= 90 + BF
= 90 + (BD^2 - FD^2)^0.5
= 90 + (90^2 - 30^2)^0.5
= 90 + 60
= 150 m
Time taken by Muong = Distance/Speed
= 150/8
= 18.75 s
Time taken by Thames to reach E:
Distance traveled by Thames = Length of side BC - Distance of point G from E
= 90 - CG
= 90 - (CD^2 - GD^2)^0.5
= 90 - (90^2 - 30^2)^0.5
= 90 - 60
= 30 m
Time taken by Thames = Distance/Speed
= 30/10
= 3 s
Therefore, they will meet at E after 18.75 seconds and 3 seconds respectively from the start.
Now, let H be the point where they meet for the second time.
Time taken by Muong to reach H:
Distance traveled by Muong = Length of side AD - Distance of point F from H
= 90 - AH
= 90 - (AE^2 - EF^2)^0.5
= 90 - (120^2 - 30^2)^0.5
= 90 - 102
= -12 m (Muong has already crossed point H)
Time taken by Muong to reach H again = Distance/Speed
= 102/8
= 12.75 s
Time taken by Thames to reach H:
Distance traveled by Thames = Length of side BC + Distance of point G from H
= 90 + HG
= 90 + (CG^2 - CH^2)^0.5
= 90 + (60^2 - 30^2)^0.5
= 90 + 51.96
= 141.96 m
Time taken by Thames to reach H = Distance/Speed
= 141.96/10
= 14.196 s
Therefore, Muong and Thames will cross each other for the second time at a distance of 10 meters from point C after 12.75 seconds and 14.196 seconds respectively from
Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s. Where shall they cross each other the second time?
Given:
Square field ABCD of side 90 m, diagonal AC is from north to south, corner B is to the west of D.
Approach:
We need to find the point where Muong and Thames will cross each other for the second time. To find that point, we need to first find the time taken by each person to reach the first intersection point (say E), and then calculate the time taken by them to reach the second intersection point.
Solution:
Let E be the point where they cross each other for the first time.
Let F be the point where Muong meets AC.
Let G be the point where Thames meets AC.
Let AB be the X-axis and BC be the Y-axis.
Let the origin be at point B.
Time taken by Muong to reach E:
Distance traveled by Muong = Length of side AB + Distance of point F from E
= 90 + BF
= 90 + (BD^2 - FD^2)^0.5
= 90 + (90^2 - 30^2)^0.5
= 90 + 60
= 150 m
Time taken by Muong = Distance/Speed
= 150/8
= 18.75 s
Time taken by Thames to reach E:
Distance traveled by Thames = Length of side BC - Distance of point G from E
= 90 - CG
= 90 - (CD^2 - GD^2)^0.5
= 90 - (90^2 - 30^2)^0.5
= 90 - 60
= 30 m
Time taken by Thames = Distance/Speed
= 30/10
= 3 s
Therefore, they will meet at E after 18.75 seconds and 3 seconds respectively from the start.
Now, let H be the point where they meet for the second time.
Time taken by Muong to reach H:
Distance traveled by Muong = Length of side AD - Distance of point F from H
= 90 - AH
= 90 - (AE^2 - EF^2)^0.5
= 90 - (120^2 - 30^2)^0.5
= 90 - 102
= -12 m (Muong has already crossed point H)
Time taken by Muong to reach H again = Distance/Speed
= 102/8
= 12.75 s
Time taken by Thames to reach H:
Distance traveled by Thames = Length of side BC + Distance of point G from H
= 90 + HG
= 90 + (CG^2 - CH^2)^0.5
= 90 + (60^2 - 30^2)^0.5
= 90 + 51.96
= 141.96 m
Time taken by Thames to reach H = Distance/Speed
= 141.96/10
= 14.196 s
Therefore, Muong and Thames will cross each other for the second time at a distance of 10 meters from point C after 12.75 seconds and 14.196 seconds respectively from
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Community Answer
A square field ABCD of side 90 m is so located that its diagonal AC i...
Clearly, the arrangement is as shown in the adjoining diagram.
It is given that Ram speed = 8 m/s.
Thames’s speed = 10 m/s
It Is clearly visible from the above figure that to meet for the first time, they have to cover a distance of 270 m i.e. three arms length of the field.
BA + AD + CD = 90 + 90 + 90 = 270 m
Since they are running in clockwise and anticlockwise direction respectively, they have to cover a di tance of 360 m (i.e. 4 arm's length of the field) for their second meeting from the first meeting point.
Thus, total distance to be covered for their second meeting = 270 + 360 = 630 m
Time required = 630/(8+10) = 630/18 = 35 seconds
Distance covered by Ram in clockwise direction In 35 seconds = 35 x 8 = 280 m
Distance covered by Thames in anticlockwise direction In 35 seconds = 35 x 10 = 350 m
Thus, Ram and Thames will meet on BC at a point 10 m from C and 80 m from B.
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A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer?
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A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer?.
A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer?.
Solutions for A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Muong and Thames start walking along the sides from B and C respectively in the clockwise and anticlockwise direction with speeds of 8 m/s and 10 m/s, Where shall they cross each other the second time?a)On AD at a distance of 30 m from Ab)On BC at a distance of 10 m from Bc)On AD at a distance of 30 m from Dd)On BC at a distance of 10 m from CCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
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