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For a particular reversible reaction at temperature T, ΔH and ΔS were found to be both +ve. If Te is the temperature at equilibrium, the reaction would be spontaneous when
  • a)
    Te > T
  • b)
    T > Te
  • c)
    Te is 5 times T
  • d)
    T = Te
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
For a particular reversible reaction at temperature T, ΔH and &D...
At equilibrium  ΔG = 0
Hence, ΔG = ΔH – TeΔS = 0

For a spontaneous reaction
ΔG must be negative which is possible only
if ΔH – TΔS < 0
∴ ΔH < TΔS
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