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For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index:
  • a)
    lies between √2 and 1
  • b)
    lies between 2 and √2
  • c)
    is less than 1
  • d)
    is greater than 2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
For the angle of minimum deviation of a prism to be equal to its refra...

The angle of minimum deviation is given as
δmin = i + e–A
for minimum deviation
δmin = A then
 2A = i + e
in case of δmin i = e
2A = 2i r1 = r2 = A/2
i =  A = 90°
from smell’s law
1 sin i = n sin r1
sin A = n sin A/2


when  A = 90° = imin
then    nmin = √2
i = A = 0  nmax = 2
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Most Upvoted Answer
For the angle of minimum deviation of a prism to be equal to its refra...
1 and 2
b)is greater than 2
c)is less than 1
d)is equal to 1

d) is equal to 1.

When the angle of minimum deviation is equal to the refracting angle, the prism is said to be in minimum deviation position. In this position, the angle of incidence and angle of emergence are equal, and the angle of deviation is minimized. This condition is achieved when the refractive index of the prism material is equal to the refractive index of the medium outside the prism (usually air), which is 1.
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For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index:a)lies between √2 and 1b)lies between 2 and √2c)is less than 1d)is greater than 2Correct answer is option 'B'. Can you explain this answer?
Question Description
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