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If f is an even function and g is an odd function, then the function fog is
  • a)
    an even function
  • b)
    an odd function
  • c)
    neither even nor odd
  • d)
    a periodic function
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Iffis an even function and g is an odd function, then the function fog...
We have, fog (–x) = f [g (–x)] = f [–g(x)
(∵ g is odd)
= f[g (x)]      (∵ f is even)
= fog (x) ∀ x ∈ R.
∴ fog is an even function.
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Iffis an even function and g is an odd function, then the function fog isa)an even functionb)an odd functionc)neither even nor oddd)a periodic functionCorrect answer is option 'A'. Can you explain this answer?
Question Description
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