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A copper sphere cools from 62°C to 50°C in 10 minutes and to 42°C in the next 10 minutes.Calculate the temperature of the surroundings.
- a)18.01ºC
- b)26ºC
- c)10.6ºC
- d)20ºC
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A copper sphere cools from 62°C to 50°C in 10 minutes and to 4...
By Newton's law of cooling,
A sphere cools from 62°C to 50°C in 10 min.
Now, sphere cools from 50°C to 42°C in next 10 min.
Dividing eqn. (2) by (3) we get,
Hence θ0 = 26°C
A sphere cools from 62°C to 50°C in 10 min.
Now, sphere cools from 50°C to 42°C in next 10 min.
Dividing eqn. (2) by (3) we get,
Hence θ0 = 26°C
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A copper sphere cools from 62°C to 50°C in 10 minutes and to 42°C in the next 10 minutes.Calculate the temperature of the surroundings.a)18.01ºCb)26ºCc)10.6ºCd)20ºCCorrect answer is option 'B'. Can you explain this answer?
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A copper sphere cools from 62°C to 50°C in 10 minutes and to 42°C in the next 10 minutes.Calculate the temperature of the surroundings.a)18.01ºCb)26ºCc)10.6ºCd)20ºCCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A copper sphere cools from 62°C to 50°C in 10 minutes and to 42°C in the next 10 minutes.Calculate the temperature of the surroundings.a)18.01ºCb)26ºCc)10.6ºCd)20ºCCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A copper sphere cools from 62°C to 50°C in 10 minutes and to 42°C in the next 10 minutes.Calculate the temperature of the surroundings.a)18.01ºCb)26ºCc)10.6ºCd)20ºCCorrect answer is option 'B'. Can you explain this answer?.
A copper sphere cools from 62°C to 50°C in 10 minutes and to 42°C in the next 10 minutes.Calculate the temperature of the surroundings.a)18.01ºCb)26ºCc)10.6ºCd)20ºCCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A copper sphere cools from 62°C to 50°C in 10 minutes and to 42°C in the next 10 minutes.Calculate the temperature of the surroundings.a)18.01ºCb)26ºCc)10.6ºCd)20ºCCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A copper sphere cools from 62°C to 50°C in 10 minutes and to 42°C in the next 10 minutes.Calculate the temperature of the surroundings.a)18.01ºCb)26ºCc)10.6ºCd)20ºCCorrect answer is option 'B'. Can you explain this answer?.
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