Calculation of Total number of electrons with n l = 5 in Mo (42) atom
1. Identifying the electronic configuration of Mo (42) atom:
- The atomic number of Molybdenum (Mo) is 42.
- The electronic configuration of Mo is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 4d5.
2. Determining the total number of electrons with n l = 5:
- Electrons with n l = 5 are those in the 5s and 5p orbitals.
- From the electronic configuration of Mo, we can see that there is 1 electron in the 5s orbital and 5 electrons in the 4d orbital.
3. Calculating the total number of electrons with n l = 5:
- Total number of electrons with n l = 5 = Number of electrons in 5s orbital + Number of electrons in 5p orbital
- Number of electrons in 5s orbital = 1
- Number of electrons in 5p orbital = 0 (as per the electronic configuration of Mo)
- Therefore, total number of electrons with n l = 5 = 1 + 0 = 1 electron.
4. Conclusion:
- In the ground state of Molybdenum (Mo) atom, there is 1 electron with n l = 5.
This detailed explanation breaks down the electronic configuration of Molybdenum (Mo) atom and helps in determining the total number of electrons with n l = 5 in its ground state.