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If a, b and c are real numbers then the roots of the equation (x – a) (x – b) + (x – b) (x – c) + (x – c) (x – a) = 0 are always
  • a)
    real
  • b)
    imaginary
  • c)
    positive
  • d)
    negative
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If a, b and c are real numbers then the roots of the equation (x &ndas...
Given equation is (x – a) (x – b) + (x – b) (x – c) + (x – c) (x – a) = 0
⇒ 3x2 – 2(b + a + c) x + ab + bc + ca = 0
Now, here A = 3, B = – 2 (a + b + c)
C = ab + bc + ca
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Most Upvoted Answer
If a, b and c are real numbers then the roots of the equation (x &ndas...
Given equation is (x – a) (x – b) + (x – b) (x – c) + (x – c) (x – a) = 0
⇒ 3x2 – 2(b + a + c) x + ab + bc + ca = 0
Now, here A = 3, B = – 2 (a + b + c)
C = ab + bc + ca
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If a, b and c are real numbers then the roots of the equation (x – a) (x – b) + (x – b) (x – c) + (x – c) (x – a) = 0 are alwaysa)realb)imaginaryc)positived)negativeCorrect answer is option 'A'. Can you explain this answer?
Question Description
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