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0.5 mole  of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area  A closed  by a massless piston.

The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end  is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]
  • a)
    (k/R) m / sec
  • b)
    (k/10R) m / sec
  • c)
    (k/100R) m / sec
  • d)
    (k/1000R) m/sec
Correct answer is option 'C'. Can you explain this answer?
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0.5 mole of an ideal gas at constant temperature 27°C kept inside ...
work done per unit time = 

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0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer?
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0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer?.
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