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0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about 0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for 0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer?.
Solutions for 0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of 0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for 0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of 0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice 0.5 mole of an ideal gas at constant temperature 27°C kept inside a cylinder of length L and crosssection area A closed by a massless piston.The cylinder is attached with a conducting rod of length L , cross-section ar ea (1/9) m2 and thermal conductivity k, whose other end is maintained at 0°C. If piston is moved such that rate of heat flow through the conducing rod is constant then velocity of piston when it is at height L/2 from the bottom of cylinder is : [Neglect any kind of heat loss from system ]a)(k/R)m / secb)(k/10R)m / secc)(k/100R)m / secd)(k/1000R)m/secCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.