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Calculate th e wavelength of ligh t used in an interference experiment from the following data : Fringe width = 0.03 cm. Distance between the slits and eyepiece through which the interference pattern is observed is 1m. Distance between the images of the virtual source when a convex lens of focal length 16 cm is used at a distance of 80 cm from the eyepiece is 0.8 cm.
  • a)
    0.0006 Å
  • b)
    0.0006 m
  • c)
    600 cm
  • d)
    6000 Å
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Calculate th e wavelength of ligh t used in an interference experiment...
Given: fringe with β = 0.03 cm, D = 1 m = 100 cm
Distance between images of the source = 0.8 cm.
Image distance v = 80 cm
Object distance = u
Using mirror formula, 
⇒ u = 20 cm
Magnification, 
Magnification 

Fringe width 
or, 
Therefore, wavelength of light used λ = 6000 Å
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Most Upvoted Answer
Calculate th e wavelength of ligh t used in an interference experiment...
To calculate the wavelength of light used in the interference experiment, we can use the formula:

λ = (d * D) / L

where λ is the wavelength, d is the fringe width, D is the distance between the slits and the eyepiece, and L is the distance between the images of the virtual source.

Given:
Fringe width (d) = 0.03 cm
Distance between slits and eyepiece (D) = 1 m = 100 cm
Distance between images of virtual source (L) = 0.8 cm

Plugging in these values into the formula, we get:

λ = (0.03 cm * 100 cm) / 0.8 cm
λ = 3.75 cm

Therefore, the wavelength of light used in the interference experiment is 3.75 cm.
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Calculate th e wavelength of ligh t used in an interference experiment from the following data : Fringe width = 0.03 cm. Distance between the slits and eyepiece through which the interference pattern is observed is 1m. Distance between the images of the virtual source when a convex lens of focal length 16 cm is used at a distance of 80 cm from the eyepiece is 0.8 cm.a)0.0006 Åb)0.0006 mc)600 cmd)6000 ÅCorrect answer is option 'D'. Can you explain this answer?
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Calculate th e wavelength of ligh t used in an interference experiment from the following data : Fringe width = 0.03 cm. Distance between the slits and eyepiece through which the interference pattern is observed is 1m. Distance between the images of the virtual source when a convex lens of focal length 16 cm is used at a distance of 80 cm from the eyepiece is 0.8 cm.a)0.0006 Åb)0.0006 mc)600 cmd)6000 ÅCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Calculate th e wavelength of ligh t used in an interference experiment from the following data : Fringe width = 0.03 cm. Distance between the slits and eyepiece through which the interference pattern is observed is 1m. Distance between the images of the virtual source when a convex lens of focal length 16 cm is used at a distance of 80 cm from the eyepiece is 0.8 cm.a)0.0006 Åb)0.0006 mc)600 cmd)6000 ÅCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate th e wavelength of ligh t used in an interference experiment from the following data : Fringe width = 0.03 cm. Distance between the slits and eyepiece through which the interference pattern is observed is 1m. Distance between the images of the virtual source when a convex lens of focal length 16 cm is used at a distance of 80 cm from the eyepiece is 0.8 cm.a)0.0006 Åb)0.0006 mc)600 cmd)6000 ÅCorrect answer is option 'D'. Can you explain this answer?.
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