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Th e beam of light h as th r ee wavelength s 4144Å, 4972Å and 6216 Å with a total intensity of 3.6 × 10–3 Wm2 equally distributed amongst the three wavelengths. The beam falls normally on the area 1 cm2 of a clean metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in 2s.a)2 × 109b)1.075 × 1012c)9 × 108d)3.75 × 106Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Th e beam of light h as th r ee wavelength s 4144Å, 4972Å and 6216 Å with a total intensity of 3.6 × 10–3 Wm2 equally distributed amongst the three wavelengths. The beam falls normally on the area 1 cm2 of a clean metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in 2s.a)2 × 109b)1.075 × 1012c)9 × 108d)3.75 × 106Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Th e beam of light h as th r ee wavelength s 4144Å, 4972Å and 6216 Å with a total intensity of 3.6 × 10–3 Wm2 equally distributed amongst the three wavelengths. The beam falls normally on the area 1 cm2 of a clean metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in 2s.a)2 × 109b)1.075 × 1012c)9 × 108d)3.75 × 106Correct answer is option 'B'. Can you explain this answer?.

Solutions for Th e beam of light h as th r ee wavelength s 4144Å, 4972Å and 6216 Å with a total intensity of 3.6 × 10–3 Wm2 equally distributed amongst the three wavelengths. The beam falls normally on the area 1 cm2 of a clean metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in 2s.a)2 × 109b)1.075 × 1012c)9 × 108d)3.75 × 106Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Th e beam of light h as th r ee wavelength s 4144Å, 4972Å and 6216 Å with a total intensity of 3.6 × 10–3 Wm2 equally distributed amongst the three wavelengths. The beam falls normally on the area 1 cm2 of a clean metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in 2s.a)2 × 109b)1.075 × 1012c)9 × 108d)3.75 × 106Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Th e beam of light h as th r ee wavelength s 4144Å, 4972Å and 6216 Å with a total intensity of 3.6 × 10–3 Wm2 equally distributed amongst the three wavelengths. The beam falls normally on the area 1 cm2 of a clean metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in 2s.a)2 × 109b)1.075 × 1012c)9 × 108d)3.75 × 106Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Th e beam of light h as th r ee wavelength s 4144Å, 4972Å and 6216 Å with a total intensity of 3.6 × 10–3 Wm2 equally distributed amongst the three wavelengths. The beam falls normally on the area 1 cm2 of a clean metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in 2s.a)2 × 109b)1.075 × 1012c)9 × 108d)3.75 × 106Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Th e beam of light h as th r ee wavelength s 4144Å, 4972Å and 6216 Å with a total intensity of 3.6 × 10–3 Wm2 equally distributed amongst the three wavelengths. The beam falls normally on the area 1 cm2 of a clean metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in 2s.a)2 × 109b)1.075 × 1012c)9 × 108d)3.75 × 106Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Th e beam of light h as th r ee wavelength s 4144Å, 4972Å and 6216 Å with a total intensity of 3.6 × 10–3 Wm2 equally distributed amongst the three wavelengths. The beam falls normally on the area 1 cm2 of a clean metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in 2s.a)2 × 109b)1.075 × 1012c)9 × 108d)3.75 × 106Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.