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Ka of HX is 10–5, then find concentration of H3O+ when equal volumes of 0.25M HX and 0.05 M NaOH are mixed.a)4 × 10–5 Mb)6 ×10–5 Mc)8 ×10–3 Md)2 ×10–5 MCorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Ka of HX is 10–5, then find concentration of H3O+ when equal volumes of 0.25M HX and 0.05 M NaOH are mixed.a)4 × 10–5 Mb)6 ×10–5 Mc)8 ×10–3 Md)2 ×10–5 MCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ka of HX is 10–5, then find concentration of H3O+ when equal volumes of 0.25M HX and 0.05 M NaOH are mixed.a)4 × 10–5 Mb)6 ×10–5 Mc)8 ×10–3 Md)2 ×10–5 MCorrect answer is option 'A'. Can you explain this answer?.

Solutions for Ka of HX is 10–5, then find concentration of H3O+ when equal volumes of 0.25M HX and 0.05 M NaOH are mixed.a)4 × 10–5 Mb)6 ×10–5 Mc)8 ×10–3 Md)2 ×10–5 MCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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