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Consider the equation of a parabola y2 + 4ax = 0, where a > 0 which of the following is/are correct?
- a)Tangent at the vertex is x = 0
- b)Directrix of the parabola is x = 0
- c)Vertex of the parabola is not at the origin
- d)Focus of the parabola is at (a, 0)
Correct answer is option 'A'. Can you explain this answer?
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Consider the equation of a parabola y2 + 4ax = 0, where a > 0 which...
Equation of parabola is y2 = – 4ax. Its focus is at(– a, 0).
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Consider the equation of a parabola y2 + 4ax = 0, where a > 0 which...
Is a constant.
The equation of a parabola in standard form is given by y^2 = 4ax, where a is a constant. This equation represents a parabola that opens either to the left or right, depending on the sign of a. If a is positive, the parabola opens to the right, and if a is negative, the parabola opens to the left.
The vertex of the parabola is at the origin (0,0) and the focus is at the point (a,0). The directrix is the line x = -a.
The equation y^2 = 4ax can also be written as y = ±√(4ax), which represents two branches of the parabola. The positive branch represents the upper half of the parabola, while the negative branch represents the lower half.
The equation y^2 = 4ax can be used to find the coordinates of other important points on the parabola, such as the vertex, focus, and directrix. These points can be determined by plugging in specific values for x.
For example, if we let x = 1, then y = ±√(4a). This gives us two points on the parabola, (1, ±√(4a)). These points are symmetric about the y-axis.
Similarly, if we let x = -1, then y = ±√(-4a). This gives us two points on the parabola, (-1, ±√(-4a)). These points are also symmetric about the y-axis.
In summary, the equation y^2 = 4ax represents a parabola that opens either to the left or right, depending on the sign of a. The vertex is at the origin, the focus is at (a,0), and the directrix is the line x = -a. The equation can be used to find the coordinates of other important points on the parabola.
The equation of a parabola in standard form is given by y^2 = 4ax, where a is a constant. This equation represents a parabola that opens either to the left or right, depending on the sign of a. If a is positive, the parabola opens to the right, and if a is negative, the parabola opens to the left.
The vertex of the parabola is at the origin (0,0) and the focus is at the point (a,0). The directrix is the line x = -a.
The equation y^2 = 4ax can also be written as y = ±√(4ax), which represents two branches of the parabola. The positive branch represents the upper half of the parabola, while the negative branch represents the lower half.
The equation y^2 = 4ax can be used to find the coordinates of other important points on the parabola, such as the vertex, focus, and directrix. These points can be determined by plugging in specific values for x.
For example, if we let x = 1, then y = ±√(4a). This gives us two points on the parabola, (1, ±√(4a)). These points are symmetric about the y-axis.
Similarly, if we let x = -1, then y = ±√(-4a). This gives us two points on the parabola, (-1, ±√(-4a)). These points are also symmetric about the y-axis.
In summary, the equation y^2 = 4ax represents a parabola that opens either to the left or right, depending on the sign of a. The vertex is at the origin, the focus is at (a,0), and the directrix is the line x = -a. The equation can be used to find the coordinates of other important points on the parabola.
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Consider the equation of a parabola y2 + 4ax = 0, where a > 0 which of the following is/are correct?a)Tangent at the vertex is x = 0b)Directrix of the parabola is x = 0c)Vertex of the parabola is not at the origind)Focus of the parabola is at (a, 0)Correct answer is option 'A'. Can you explain this answer?
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Consider the equation of a parabola y2 + 4ax = 0, where a > 0 which of the following is/are correct?a)Tangent at the vertex is x = 0b)Directrix of the parabola is x = 0c)Vertex of the parabola is not at the origind)Focus of the parabola is at (a, 0)Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider the equation of a parabola y2 + 4ax = 0, where a > 0 which of the following is/are correct?a)Tangent at the vertex is x = 0b)Directrix of the parabola is x = 0c)Vertex of the parabola is not at the origind)Focus of the parabola is at (a, 0)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the equation of a parabola y2 + 4ax = 0, where a > 0 which of the following is/are correct?a)Tangent at the vertex is x = 0b)Directrix of the parabola is x = 0c)Vertex of the parabola is not at the origind)Focus of the parabola is at (a, 0)Correct answer is option 'A'. Can you explain this answer?.
Consider the equation of a parabola y2 + 4ax = 0, where a > 0 which of the following is/are correct?a)Tangent at the vertex is x = 0b)Directrix of the parabola is x = 0c)Vertex of the parabola is not at the origind)Focus of the parabola is at (a, 0)Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider the equation of a parabola y2 + 4ax = 0, where a > 0 which of the following is/are correct?a)Tangent at the vertex is x = 0b)Directrix of the parabola is x = 0c)Vertex of the parabola is not at the origind)Focus of the parabola is at (a, 0)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the equation of a parabola y2 + 4ax = 0, where a > 0 which of the following is/are correct?a)Tangent at the vertex is x = 0b)Directrix of the parabola is x = 0c)Vertex of the parabola is not at the origind)Focus of the parabola is at (a, 0)Correct answer is option 'A'. Can you explain this answer?.
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