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What is the change in oxidation number of carbon in the following reaction? (2020) CH4(g) 4Cl2(g) → CCl4(l) 4HCl(g) (a) -4 to 4 (b) 0 to -4 (c) 4 to 4 (d) 0 to 4?
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What is the change in oxidation number of carbon in the following reac...
The change in oxidation number of carbon in the given reaction is from -4 to +4.

Explanation:

The oxidation number of an element in a compound indicates the number of electrons that element has gained or lost. In order to determine the change in oxidation number of carbon in the given reaction, we need to assign oxidation numbers to carbon in each compound involved.

Assigning oxidation numbers:

1. CH4 (methane): The oxidation number of hydrogen (H) is always +1, and since there are four hydrogen atoms in methane, the total oxidation number of hydrogen is +4. The sum of the oxidation numbers in a neutral molecule is always zero, so the oxidation number of carbon (C) in methane is -4.

2. CCl4 (carbon tetrachloride): The oxidation number of chlorine (Cl) is -1. Since there are four chlorine atoms in carbon tetrachloride, the total oxidation number of chlorine is -4. The sum of the oxidation numbers in a neutral molecule is always zero, so the oxidation number of carbon in carbon tetrachloride is +4.

Change in oxidation number:

By comparing the oxidation numbers of carbon in the reactant (CH4) and the product (CCl4), we can see that the oxidation number of carbon has changed from -4 to +4. This indicates that carbon has undergone oxidation in the reaction.

Conclusion:

The change in oxidation number of carbon in the given reaction is from -4 to +4. Therefore, the correct answer is option (a) -4 to +4.
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What is the change in oxidation number of carbon in the following reac...
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What is the change in oxidation number of carbon in the following reaction? (2020) CH4(g) 4Cl2(g) → CCl4(l) 4HCl(g) (a) -4 to 4 (b) 0 to -4 (c) 4 to 4 (d) 0 to 4?
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