Which of the following is irrational?a)Product of (3 - √27) and (√9 +...
Product of (3 - √27) and (√9 + 3√3)
= (3 - 3√3)(3 + 3√3)
= - 18 (which is not irrational)
Option (2):
= Sum of (5 - 4√2) and 4(6 + √2)
= (5 - 4√2) + 4(6 + √2)
= 5 - 4√2 + 24 + 4√2
= 29 (which is not irrational)
Option (3):
= Sum of √4761 and √5175
= 69 + 15√23 (which is irrational)
Option (4):
= Product of √16875 and √27
= 75√3 x 3√3
= 675 (which is not irrational)
Which of the following is irrational?a)Product of (3 - √27) and (√9 +...
Understanding the Problem
To determine which option is irrational, we need to analyze each expression carefully. An irrational number cannot be expressed as a simple fraction, while a rational number can.
Option A: Product of (3 - √27) and (√9 + 3√3)
- Calculate √27 = 3√3
- Thus, 3 - √27 = 3 - 3√3 (this is irrational)
- √9 = 3, so √9 + 3√3 = 3 + 3√3 (this is also irrational)
- The product of two irrational numbers can be either rational or irrational; hence, we cannot conclude yet.
Option B: Sum of (5 - 4√2) and 4(6 + √2)
- Simplify: 4(6 + √2) = 24 + 4√2
- Now, (5 - 4√2) + (24 + 4√2) = 29 (this is rational)
Option C: Sum of √4761 and √5175
- Calculate √4761 = 69 (since 69 * 69 = 4761, it's rational)
- Calculate √5175 = √(25 * 207) = 5√207 (√207 is irrational)
- Therefore, 69 + 5√207 is irrational, as the sum of a rational and an irrational number is irrational.
Option D: Product of √16875 and √27
- √16875 = √(25 * 675) = 5√675, which is rational.
- √27 = 3√3, which is also irrational.
- The product of an irrational number and a rational number can be irrational, but we need to verify further.
Conclusion
The only option that yields an irrational result is Option C, where the sum of a rational number and an irrational number produces an irrational number.