JEE Exam  >  JEE Questions  >  Two capacitors with capacitance values C1 = 2... Start Learning for Free
Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2 = 3000 ± 15 pF are connected in series. The voltage applied across this combination is V = 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______. 
    Correct answer is '1.30'. Can you explain this answer?
    Verified Answer
    Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2...

    View all questions of this test
    Most Upvoted Answer
    Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2...
    ΜF and C2 = 3000 µF are connected in parallel. The total capacitance when the two capacitors are connected in parallel can be calculated by adding their capacitance values:

    C_total = C1 + C2
    = 2000 µF + 3000 µF
    = 5000 µF

    Therefore, the total capacitance when the two capacitors are connected in parallel is 5000 µF.
    Explore Courses for JEE exam

    Similar JEE Doubts

    Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2= 3000 ± 15 pF are connected in series. The voltage applied across this combination is V= 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______.Correct answer is '1.30'. Can you explain this answer?
    Question Description
    Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2= 3000 ± 15 pF are connected in series. The voltage applied across this combination is V= 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______.Correct answer is '1.30'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2= 3000 ± 15 pF are connected in series. The voltage applied across this combination is V= 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______.Correct answer is '1.30'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2= 3000 ± 15 pF are connected in series. The voltage applied across this combination is V= 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______.Correct answer is '1.30'. Can you explain this answer?.
    Solutions for Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2= 3000 ± 15 pF are connected in series. The voltage applied across this combination is V= 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______.Correct answer is '1.30'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
    Here you can find the meaning of Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2= 3000 ± 15 pF are connected in series. The voltage applied across this combination is V= 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______.Correct answer is '1.30'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2= 3000 ± 15 pF are connected in series. The voltage applied across this combination is V= 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______.Correct answer is '1.30'. Can you explain this answer?, a detailed solution for Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2= 3000 ± 15 pF are connected in series. The voltage applied across this combination is V= 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______.Correct answer is '1.30'. Can you explain this answer? has been provided alongside types of Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2= 3000 ± 15 pF are connected in series. The voltage applied across this combination is V= 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______.Correct answer is '1.30'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Two capacitors with capacitance values C1 = 2000 ± 10 pF and C2= 3000 ± 15 pF are connected in series. The voltage applied across this combination is V= 5.00 ± 0.02 V. The percentage error in the calculation of the energy stored in this combination of capacitors is _______.Correct answer is '1.30'. Can you explain this answer? tests, examples and also practice JEE tests.
    Explore Courses for JEE exam

    Top Courses for JEE

    Explore Courses
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev