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In the chemical reaction between stoichiometric quantities of KMnO4 and KI in weakly basic solution, what is the number of moles of I2 released for 4 moles of KMnO4 consumed ?
Correct answer is '6'. Can you explain this answer?
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Verified Answer
In the chemical reaction between stoichiometric quantities of KMnO4 an...
KMnO4 + KI → MnO2 + I2
Eq of KMnO4 = Eq of I2
4 × 3 = n × 2
n = 6
Eq of KMnO4 = Eq of I2
4 × 3 = n × 2
n = 6
Most Upvoted Answer
In the chemical reaction between stoichiometric quantities of KMnO4 an...
Solution:
The given chemical reaction is:
2KMnO4 + 10KI + 8H2O → 2MnO2 + 5I2 + 2KOH + 8H2O
From the balanced chemical equation, we can see that:
- 2 moles of KMnO4 react with 10 moles of KI to produce 5 moles of I2
- Therefore, 4 moles of KMnO4 will react with 20 moles of KI to produce 10 moles of I2
- However, the reaction takes place in weakly basic solution, which means that some of the iodine produced will react with hydroxide ions (OH-) to form iodide ions (I-)
- From the balanced chemical equation, we can see that the reaction produces 2 moles of KOH for every 2 moles of KMnO4 consumed
- Therefore, for 4 moles of KMnO4 consumed, the reaction will produce 4 moles of KOH
- These 4 moles of KOH will react with 4 moles of I2 to form 4 moles of KI and 2 moles of water (H2O)
- Therefore, out of the 10 moles of I2 produced, 4 moles will react with KOH to form KI and H2O, leaving 6 moles of I2 unreacted and released
Hence, the number of moles of I2 released for 4 moles of KMnO4 consumed is 6.
The given chemical reaction is:
2KMnO4 + 10KI + 8H2O → 2MnO2 + 5I2 + 2KOH + 8H2O
From the balanced chemical equation, we can see that:
- 2 moles of KMnO4 react with 10 moles of KI to produce 5 moles of I2
- Therefore, 4 moles of KMnO4 will react with 20 moles of KI to produce 10 moles of I2
- However, the reaction takes place in weakly basic solution, which means that some of the iodine produced will react with hydroxide ions (OH-) to form iodide ions (I-)
- From the balanced chemical equation, we can see that the reaction produces 2 moles of KOH for every 2 moles of KMnO4 consumed
- Therefore, for 4 moles of KMnO4 consumed, the reaction will produce 4 moles of KOH
- These 4 moles of KOH will react with 4 moles of I2 to form 4 moles of KI and 2 moles of water (H2O)
- Therefore, out of the 10 moles of I2 produced, 4 moles will react with KOH to form KI and H2O, leaving 6 moles of I2 unreacted and released
Hence, the number of moles of I2 released for 4 moles of KMnO4 consumed is 6.
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In the chemical reaction between stoichiometric quantities of KMnO4 and KI in weakly basic solution, what is the number of moles of I2 released for 4 moles of KMnO4 consumed ?Correct answer is '6'. Can you explain this answer?
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In the chemical reaction between stoichiometric quantities of KMnO4 and KI in weakly basic solution, what is the number of moles of I2 released for 4 moles of KMnO4 consumed ?Correct answer is '6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the chemical reaction between stoichiometric quantities of KMnO4 and KI in weakly basic solution, what is the number of moles of I2 released for 4 moles of KMnO4 consumed ?Correct answer is '6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the chemical reaction between stoichiometric quantities of KMnO4 and KI in weakly basic solution, what is the number of moles of I2 released for 4 moles of KMnO4 consumed ?Correct answer is '6'. Can you explain this answer?.
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