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Projectile motion to orbital motion:If we throw a ball horizontally with a speed 8000 m/s off the surface of the Earth (and there are no obstructions in the way) how far will it travel in the vertical and horizontal directions in 1 second? (Ignore the air resistance)vx = 8000 m/st = 1sSo, horizontally it will movevyt = 8000 mVy = 0t = 1sg = 10 m/s2So, vertically it will move down1/2 gt2 = 5 mBut the curvature of the Earth changes by 5m in every 8000 m. So, will the ball ever touch the earth? The answer is NO! The ball will continually falls in free fall around the Earth and ultimately it will be orbiting around the Earth!If v = 8000 m/s the orbit will be circular.If v is within the range 8000 m/s to 11200 m/s, then the orbit will be elliptical. 11200 m/s is the velocity required to escape the earth. Escape velocity is the velocity of the projectile body that is sufficient for it to escape the gravitational attraction of earth. 42500 m/s is the velocity required to escape the Solar System!Curvature of the Earth changes by………... in everya)5m, 8000 kmb)5m, 8 kmc)0.005 km, 8 kmd)5m, 80000 mCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Projectile motion to orbital motion:If we throw a ball horizontally with a speed 8000 m/s off the surface of the Earth (and there are no obstructions in the way) how far will it travel in the vertical and horizontal directions in 1 second? (Ignore the air resistance)vx = 8000 m/st = 1sSo, horizontally it will movevyt = 8000 mVy = 0t = 1sg = 10 m/s2So, vertically it will move down1/2 gt2 = 5 mBut the curvature of the Earth changes by 5m in every 8000 m. So, will the ball ever touch the earth? The answer is NO! The ball will continually falls in free fall around the Earth and ultimately it will be orbiting around the Earth!If v = 8000 m/s the orbit will be circular.If v is within the range 8000 m/s to 11200 m/s, then the orbit will be elliptical. 11200 m/s is the velocity required to escape the earth. Escape velocity is the velocity of the projectile body that is sufficient for it to escape the gravitational attraction of earth. 42500 m/s is the velocity required to escape the Solar System!Curvature of the Earth changes by………... in everya)5m, 8000 kmb)5m, 8 kmc)0.005 km, 8 kmd)5m, 80000 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Projectile motion to orbital motion:If we throw a ball horizontally with a speed 8000 m/s off the surface of the Earth (and there are no obstructions in the way) how far will it travel in the vertical and horizontal directions in 1 second? (Ignore the air resistance)vx = 8000 m/st = 1sSo, horizontally it will movevyt = 8000 mVy = 0t = 1sg = 10 m/s2So, vertically it will move down1/2 gt2 = 5 mBut the curvature of the Earth changes by 5m in every 8000 m. So, will the ball ever touch the earth? The answer is NO! The ball will continually falls in free fall around the Earth and ultimately it will be orbiting around the Earth!If v = 8000 m/s the orbit will be circular.If v is within the range 8000 m/s to 11200 m/s, then the orbit will be elliptical. 11200 m/s is the velocity required to escape the earth. Escape velocity is the velocity of the projectile body that is sufficient for it to escape the gravitational attraction of earth. 42500 m/s is the velocity required to escape the Solar System!Curvature of the Earth changes by………... in everya)5m, 8000 kmb)5m, 8 kmc)0.005 km, 8 kmd)5m, 80000 mCorrect answer is option 'B'. Can you explain this answer?.

Solutions for Projectile motion to orbital motion:If we throw a ball horizontally with a speed 8000 m/s off the surface of the Earth (and there are no obstructions in the way) how far will it travel in the vertical and horizontal directions in 1 second? (Ignore the air resistance)vx = 8000 m/st = 1sSo, horizontally it will movevyt = 8000 mVy = 0t = 1sg = 10 m/s2So, vertically it will move down1/2 gt2 = 5 mBut the curvature of the Earth changes by 5m in every 8000 m. So, will the ball ever touch the earth? The answer is NO! The ball will continually falls in free fall around the Earth and ultimately it will be orbiting around the Earth!If v = 8000 m/s the orbit will be circular.If v is within the range 8000 m/s to 11200 m/s, then the orbit will be elliptical. 11200 m/s is the velocity required to escape the earth. Escape velocity is the velocity of the projectile body that is sufficient for it to escape the gravitational attraction of earth. 42500 m/s is the velocity required to escape the Solar System!Curvature of the Earth changes by………... in everya)5m, 8000 kmb)5m, 8 kmc)0.005 km, 8 kmd)5m, 80000 mCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of Projectile motion to orbital motion:If we throw a ball horizontally with a speed 8000 m/s off the surface of the Earth (and there are no obstructions in the way) how far will it travel in the vertical and horizontal directions in 1 second? (Ignore the air resistance)vx = 8000 m/st = 1sSo, horizontally it will movevyt = 8000 mVy = 0t = 1sg = 10 m/s2So, vertically it will move down1/2 gt2 = 5 mBut the curvature of the Earth changes by 5m in every 8000 m. So, will the ball ever touch the earth? The answer is NO! The ball will continually falls in free fall around the Earth and ultimately it will be orbiting around the Earth!If v = 8000 m/s the orbit will be circular.If v is within the range 8000 m/s to 11200 m/s, then the orbit will be elliptical. 11200 m/s is the velocity required to escape the earth. Escape velocity is the velocity of the projectile body that is sufficient for it to escape the gravitational attraction of earth. 42500 m/s is the velocity required to escape the Solar System!Curvature of the Earth changes by………... in everya)5m, 8000 kmb)5m, 8 kmc)0.005 km, 8 kmd)5m, 80000 mCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Projectile motion to orbital motion:If we throw a ball horizontally with a speed 8000 m/s off the surface of the Earth (and there are no obstructions in the way) how far will it travel in the vertical and horizontal directions in 1 second? (Ignore the air resistance)vx = 8000 m/st = 1sSo, horizontally it will movevyt = 8000 mVy = 0t = 1sg = 10 m/s2So, vertically it will move down1/2 gt2 = 5 mBut the curvature of the Earth changes by 5m in every 8000 m. So, will the ball ever touch the earth? The answer is NO! The ball will continually falls in free fall around the Earth and ultimately it will be orbiting around the Earth!If v = 8000 m/s the orbit will be circular.If v is within the range 8000 m/s to 11200 m/s, then the orbit will be elliptical. 11200 m/s is the velocity required to escape the earth. Escape velocity is the velocity of the projectile body that is sufficient for it to escape the gravitational attraction of earth. 42500 m/s is the velocity required to escape the Solar System!Curvature of the Earth changes by………... in everya)5m, 8000 kmb)5m, 8 kmc)0.005 km, 8 kmd)5m, 80000 mCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Projectile motion to orbital motion:If we throw a ball horizontally with a speed 8000 m/s off the surface of the Earth (and there are no obstructions in the way) how far will it travel in the vertical and horizontal directions in 1 second? (Ignore the air resistance)vx = 8000 m/st = 1sSo, horizontally it will movevyt = 8000 mVy = 0t = 1sg = 10 m/s2So, vertically it will move down1/2 gt2 = 5 mBut the curvature of the Earth changes by 5m in every 8000 m. So, will the ball ever touch the earth? The answer is NO! The ball will continually falls in free fall around the Earth and ultimately it will be orbiting around the Earth!If v = 8000 m/s the orbit will be circular.If v is within the range 8000 m/s to 11200 m/s, then the orbit will be elliptical. 11200 m/s is the velocity required to escape the earth. Escape velocity is the velocity of the projectile body that is sufficient for it to escape the gravitational attraction of earth. 42500 m/s is the velocity required to escape the Solar System!Curvature of the Earth changes by………... in everya)5m, 8000 kmb)5m, 8 kmc)0.005 km, 8 kmd)5m, 80000 mCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Projectile motion to orbital motion:If we throw a ball horizontally with a speed 8000 m/s off the surface of the Earth (and there are no obstructions in the way) how far will it travel in the vertical and horizontal directions in 1 second? (Ignore the air resistance)vx = 8000 m/st = 1sSo, horizontally it will movevyt = 8000 mVy = 0t = 1sg = 10 m/s2So, vertically it will move down1/2 gt2 = 5 mBut the curvature of the Earth changes by 5m in every 8000 m. So, will the ball ever touch the earth? The answer is NO! The ball will continually falls in free fall around the Earth and ultimately it will be orbiting around the Earth!If v = 8000 m/s the orbit will be circular.If v is within the range 8000 m/s to 11200 m/s, then the orbit will be elliptical. 11200 m/s is the velocity required to escape the earth. Escape velocity is the velocity of the projectile body that is sufficient for it to escape the gravitational attraction of earth. 42500 m/s is the velocity required to escape the Solar System!Curvature of the Earth changes by………... in everya)5m, 8000 kmb)5m, 8 kmc)0.005 km, 8 kmd)5m, 80000 mCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Projectile motion to orbital motion:If we throw a ball horizontally with a speed 8000 m/s off the surface of the Earth (and there are no obstructions in the way) how far will it travel in the vertical and horizontal directions in 1 second? (Ignore the air resistance)vx = 8000 m/st = 1sSo, horizontally it will movevyt = 8000 mVy = 0t = 1sg = 10 m/s2So, vertically it will move down1/2 gt2 = 5 mBut the curvature of the Earth changes by 5m in every 8000 m. So, will the ball ever touch the earth? The answer is NO! The ball will continually falls in free fall around the Earth and ultimately it will be orbiting around the Earth!If v = 8000 m/s the orbit will be circular.If v is within the range 8000 m/s to 11200 m/s, then the orbit will be elliptical. 11200 m/s is the velocity required to escape the earth. Escape velocity is the velocity of the projectile body that is sufficient for it to escape the gravitational attraction of earth. 42500 m/s is the velocity required to escape the Solar System!Curvature of the Earth changes by………... in everya)5m, 8000 kmb)5m, 8 kmc)0.005 km, 8 kmd)5m, 80000 mCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.