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A circular disc of radius R carries surface charge densitywhere σ0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is φ0. Electric flux through another spherical surface of radius R/4and concentric with the disc is φ. Then the ratiois ......Correct answer is '6.40'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A circular disc of radius R carries surface charge densitywhere σ0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is φ0. Electric flux through another spherical surface of radius R/4and concentric with the disc is φ. Then the ratiois ......Correct answer is '6.40'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circular disc of radius R carries surface charge densitywhere σ0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is φ0. Electric flux through another spherical surface of radius R/4and concentric with the disc is φ. Then the ratiois ......Correct answer is '6.40'. Can you explain this answer?.

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Here you can find the meaning of A circular disc of radius R carries surface charge densitywhere σ0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is φ0. Electric flux through another spherical surface of radius R/4and concentric with the disc is φ. Then the ratiois ......Correct answer is '6.40'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A circular disc of radius R carries surface charge densitywhere σ0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is φ0. Electric flux through another spherical surface of radius R/4and concentric with the disc is φ. Then the ratiois ......Correct answer is '6.40'. Can you explain this answer?, a detailed solution for A circular disc of radius R carries surface charge densitywhere σ0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is φ0. Electric flux through another spherical surface of radius R/4and concentric with the disc is φ. Then the ratiois ......Correct answer is '6.40'. Can you explain this answer? has been provided alongside types of A circular disc of radius R carries surface charge densitywhere σ0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is φ0. Electric flux through another spherical surface of radius R/4and concentric with the disc is φ. Then the ratiois ......Correct answer is '6.40'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A circular disc of radius R carries surface charge densitywhere σ0 is a constant and r is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is φ0. Electric flux through another spherical surface of radius R/4and concentric with the disc is φ. Then the ratiois ......Correct answer is '6.40'. Can you explain this answer? tests, examples and also practice JEE tests.