Find the general solution dy/dx=1-cosx/1+cosx
General Solution of dy/dx = (1 - cos(x))/(1 + cos(x)):
To find the general solution of the given differential equation dy/dx = (1 - cos(x))/(1 + cos(x)), we will use separation of variables and integrate both sides.
Separation of Variables:
Separation of variables allows us to separate the variables, y and x, onto opposite sides of the equation.
dy/dx = (1 - cos(x))/(1 + cos(x))
We can rewrite the equation as:
(1 + cos(x)) dy = (1 - cos(x)) dx
Integration:
Now, we will integrate both sides of the equation with respect to their respective variables.
∫(1 + cos(x)) dy = ∫(1 - cos(x)) dx
Integrating the left side with respect to y gives us:
y + ∫cos(x) dy = x + ∫(1 - cos(x)) dx
Simplifying further:
y + ∫cos(x) dy = x + ∫dx - ∫cos(x) dx
The integral of dx is x, and the integral of cos(x) dx is sin(x):
y + y sin(x) = x + (x - sin(x))
Combining like terms:
y(1 + sin(x)) = 2x - sin(x)
Isolating y:
To find the general solution, we need to isolate y. Divide both sides of the equation by (1 + sin(x)):
y = (2x - sin(x))/(1 + sin(x))
General Solution:
Thus, the general solution of the given differential equation dy/dx = (1 - cos(x))/(1 + cos(x)) is:
y = (2x - sin(x))/(1 + sin(x))
This equation represents the family of all possible solutions to the given differential equation.
Find the general solution dy/dx=1-cosx/1+cosx
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