Class 12 Exam > Class 12 Questions > Directions : Read the passage given below and...
Start Learning for Free
Directions : Read the passage given below and answer the following questions:
The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.
For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).
Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water is
The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.
For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).
Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water is
- a)17.2
- b)17.4
- c)17.120
- d)17.02
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Directions : Read the passage given below and answer the following que...
Vapour pressure of water, p1° = 17.535 mm of Hg
Mass of glucose, w2 = 25 g
Mass of water, w1 = 450 g
We know that,
Molar mass of glucose (C6H12O6),
M2 = 6 × 12 + 12 × 1 + 6 × 16 = 180 g mol - 1
Molar mass of water, M1 = 18 g mol- 1
Then, number of moles of glucose, n1 = 25/180 = 0.139 mol
And, number of moles of water, n2 =450/18 = 25 mol
Now, we know that,
(p1° - p°) / p1° = n1 / n2 + n1
⇒ 17.535 - p° / 17.535 = 0.139 / (0.139+25)
⇒ 17.535 - p1 = 0.097
⇒ p1 = 17.44 mm of Hg
Hence, the vapour pressure of water is 17.44 mm of Hg.
Mass of glucose, w2 = 25 g
Mass of water, w1 = 450 g
We know that,
Molar mass of glucose (C6H12O6),
M2 = 6 × 12 + 12 × 1 + 6 × 16 = 180 g mol - 1
Molar mass of water, M1 = 18 g mol- 1
Then, number of moles of glucose, n1 = 25/180 = 0.139 mol
And, number of moles of water, n2 =450/18 = 25 mol
Now, we know that,
(p1° - p°) / p1° = n1 / n2 + n1
⇒ 17.535 - p° / 17.535 = 0.139 / (0.139+25)
⇒ 17.535 - p1 = 0.097
⇒ p1 = 17.44 mm of Hg
Hence, the vapour pressure of water is 17.44 mm of Hg.
Most Upvoted Answer
Directions : Read the passage given below and answer the following que...
Colligative Properties and Relative Lowering in Vapour Pressure
- Colligative properties are properties of solutions that depend only on the number of solute particles and not on the nature of the solute.
- Relative lowering in vapour pressure is an example of a colligative property.
- In this experiment, the lowering in vapour pressure of a sugar solution was found to be 0.061 mm of Hg.
Calculating Vapour Pressure of Water with Glucose Solution
- To calculate the vapour pressure of water with glucose solution, we need to use the formula for relative lowering in vapour pressure.
- The formula is:
ΔP/P₀ = (n₂/n₁)
Where ΔP is the lowering in vapour pressure, P₀ is the vapour pressure of the pure solvent (water), n₂ is the number of particles of solute (glucose) and n₁ is the number of particles of solvent (water).
- We are given that the vapour pressure of water at 20°C is 17.5 mm of Hg and that 25g of glucose is dissolved in 450g of water.
- First, we need to calculate the number of particles of glucose and water.
- To do this, we use the formula:
n = m/M
Where n is the number of particles, m is the mass of the substance and M is the molar mass.
- The molar mass of glucose is 180 g/mol.
- Therefore, the number of particles of glucose is:
n₂ = 25g / 180 g/mol = 0.139 mol
- The molar mass of water is 18 g/mol.
- Therefore, the number of particles of water is:
n₁ = 450g / 18 g/mol = 25 mol
- Now, we can substitute these values into the formula for relative lowering in vapour pressure:
ΔP/P₀ = (n₂/n₁)
ΔP/17.5 = (0.139/25)
ΔP = 0.077 mm of Hg
- Finally, we can calculate the vapour pressure of water with glucose solution:
P = P₀ - ΔP
P = 17.5 - 0.077
P = 17.423 mm of Hg
- Therefore, the answer is option B, 17.4 mm of Hg.
- Colligative properties are properties of solutions that depend only on the number of solute particles and not on the nature of the solute.
- Relative lowering in vapour pressure is an example of a colligative property.
- In this experiment, the lowering in vapour pressure of a sugar solution was found to be 0.061 mm of Hg.
Calculating Vapour Pressure of Water with Glucose Solution
- To calculate the vapour pressure of water with glucose solution, we need to use the formula for relative lowering in vapour pressure.
- The formula is:
ΔP/P₀ = (n₂/n₁)
Where ΔP is the lowering in vapour pressure, P₀ is the vapour pressure of the pure solvent (water), n₂ is the number of particles of solute (glucose) and n₁ is the number of particles of solvent (water).
- We are given that the vapour pressure of water at 20°C is 17.5 mm of Hg and that 25g of glucose is dissolved in 450g of water.
- First, we need to calculate the number of particles of glucose and water.
- To do this, we use the formula:
n = m/M
Where n is the number of particles, m is the mass of the substance and M is the molar mass.
- The molar mass of glucose is 180 g/mol.
- Therefore, the number of particles of glucose is:
n₂ = 25g / 180 g/mol = 0.139 mol
- The molar mass of water is 18 g/mol.
- Therefore, the number of particles of water is:
n₁ = 450g / 18 g/mol = 25 mol
- Now, we can substitute these values into the formula for relative lowering in vapour pressure:
ΔP/P₀ = (n₂/n₁)
ΔP/17.5 = (0.139/25)
ΔP = 0.077 mm of Hg
- Finally, we can calculate the vapour pressure of water with glucose solution:
P = P₀ - ΔP
P = 17.5 - 0.077
P = 17.423 mm of Hg
- Therefore, the answer is option B, 17.4 mm of Hg.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer?
Question Description
Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer?.
Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer?.
Solutions for Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Directions : Read the passage given below and answer the following questions:The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water isa)17.2b)17.4c)17.120d)17.02Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup