A peak rectifier is a circuit that converts an AC voltage signal into a DC voltage signal. It is also known as a half-wave rectifier because it uses only one half of the input signal. The circuit consists of a diode, a load resistor, and a capacitor.


The fraction of the cycle during which the diode is conducting is known as the conduction angle. In the case of a peak rectifier, the diode conducts only during the positive half-cycle of the AC input signal.


The diode conducts when the input voltage is greater than the forward voltage drop across the diode. The forward voltage drop across a silicon diode is typically 0.7V.

The peak voltage of the input signal is 100V. Therefore, the diode conducts when the input voltage is greater than 0.7V.

The equation for the voltage across the load resistor is given by:
Vout = Vp - Vf
where Vp is the peak voltage of the input signal and Vf is the forward voltage drop across the diode.

Substituting the values, we get:
Vout = 100V - 0.7V
Vout = 99.3V

The current through the load resistor is given by:
I = Vout / R
where R is the load resistance.

Substituting the values, we get:
I = 99.3V / 10000ohm
I = 0.00993A

The power dissipated by the load resistor is given by:
P = I^2 * R

Substituting the values, we get:
P = (0.00993A)^2 * 10000ohm
P = 0.987W

The conduction angle is given by:
Conduction angle = (1/2π) * ∫(t1 to t2) sin(ωt) dt

where t1 and t2 are the times at which the diode starts and stops conducting, respectively.

The time period of the input signal is given by:
T = 1/f
where f is the frequency of the input signal.

Substituting the values, we get:
T = 1/60Hz
T = 0.0167s

During the positive half-cycle, the diode conducts when the input voltage is greater than 0.7V. Therefore, the diode starts conducting at an angle of:
θ1 = sin^-1(0.7V/100V)
θ1 = 0.4496 radians

The diode stops conducting when the input voltage becomes negative. Therefore, the diode stops conducting at an angle of:
θ2 = π radians

Substituting the values, we get:
Conduction angle = (1/2π) * ∫(0.4496 to π) sin(ωt) dt
Conduction angle = 0.318 radians

Therefore, the fraction of the cycle during which the diode is conducting is:
Diode conducting fraction = Conduction angle / π
Diode conducting fraction = 0.101 or 10.1