If body travels a distance of 2 m in 2 second and 2.8 in next 4 seconds what will be the speed of body at the end of the 10th is again from the start?

Question

Answer

Answer:

Given:

Distance travelled in first 2 seconds = 2 m

Distance travelled in next 4 seconds = 2.8 m

To find: Speed of body at the end of 10 seconds from the start.

Calculations:

Calculation of Average Speed:

The distance travelled in the first 2 seconds and next 4 seconds are given. We can calculate the total distance travelled by adding these two values.

Total distance travelled = 2 m + 2.8 m = 4.8 m

The time taken to cover this distance is 2 seconds + 4 seconds = 6 seconds

Therefore, the average speed of the body is:

Average speed = Total distance travelled / Total time taken

Average speed = 4.8 m / 6 s = 0.8 m/s

Calculation of Final Speed:

Now, we need to calculate the final speed of the body at the end of 10 seconds from the start.

Let's assume that the body moves with a constant speed after the first 6 seconds. Therefore, the distance covered in the next 4 seconds is:

Distance covered in the next 4 seconds = Speed x Time

Distance covered in the next 4 seconds = 0.8 m/s x 4 s = 3.2 m

The total distance travelled in 10 seconds is:

Total distance travelled = Distance travelled in the first 6 seconds + Distance travelled in the next 4 seconds

Total distance travelled = 2 m + 2.8 m + 3.2 m = 8 m

The time taken to cover this distance is 10 seconds.

The final speed of the body is:

Final speed = Total distance travelled / Total time taken

Final speed = 8 m / 10 s = 0.8 m/s

Conclusion:

Therefore, the speed of the body at the end of 10 seconds from the start is 0.8 m/s.

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