The rate of monthly salary of a man increases annually in A.P. He was ...
**Given Information:**
- The rate of monthly salary of a man increases annually in A.P.
- He was drawing Rs 40,000 per month during the eleventh year of his service.
- He was drawing Rs 76,000 per month during the 29th year of his service.
- He has completed 36 years of service.
**To Find:**
- His starting salary and the rate of annual increment.
- His salary at the time of his retirement.
**Solution:**
**Step 1: Finding the Common Difference (d):**
We know that the rate of monthly salary increases annually in A.P. Let's assume that the increment in salary each year is 'd'.
During the eleventh year of service, the salary was Rs 40,000.
So, the salary during the 12th year would be Rs 40,000 + d.
Similarly, the salary during the 29th year of service was Rs 76,000.
So, the salary during the 30th year would be Rs 76,000 + d.
Therefore, we can write two equations based on the given information:
40,000 + 10d = 40,000
76,000 + 29d = 76,000
Simplifying the equations, we get:
10d = 0
29d = 0
From these equations, we can conclude that the common difference (d) is zero.
**Step 2: Finding the Starting Salary (a):**
Since the common difference (d) is zero, it means that there is no increment in the salary each year. Therefore, the salary remains constant throughout the service period.
During the 11th year of service, the salary was Rs 40,000.
Therefore, the starting salary (a) is also Rs 40,000.
**Step 3: Finding the Salary at the Time of Retirement:**
The man has completed 36 years of service.
Since there is no increment in the salary each year, the salary remains constant at Rs 40,000.
Therefore, his salary at the time of retirement, just on the completion of 36 years of service, would be Rs 40,000.
**Conclusion:**
- The starting salary of the man is Rs 40,000 and there is no increment in the salary each year.
- His salary at the time of retirement, just on the completion of 36 years of service, would also be Rs 40,000.