Tank A contains 6 times as much water as Tank B. How much water must M...
Let quantity of water in tank B be x litres.
Then quantity of water in the tank A=6x litres
Total water in both the tanks =x+6x
=140 liters
⇒7x=140⇒x=20
∴ Water in tank B=20 litres
⇒ Water in tank A=20×6=120 litres
So, quantity of water to be transferred from tank A to tank B, so that each tank contains 70 litres= 70 −20=50 litres
Therefore, 50 liters of water should be transferred.
View all questions of this test
Tank A contains 6 times as much water as Tank B. How much water must M...
Given:
- Tank A contains 6 times as much water as Tank B
- Each tank should contain 70 litres of water
To find:
- How much water must be transferred from Tank A to Tank B
Solution:
Let the amount of water in Tank B be x litres
Then, the amount of water in Tank A = 6x litres
As per the question,
Water in Tank A + Water in Tank B = Total water = 6x + x = 7x litres
Also, each tank should contain 70 litres of water.
So,
Water in Tank A + Water transferred from Tank A to Tank B = 70 litres
Water in Tank B + Water transferred from Tank A to Tank B = 70 litres
Simplifying these equations, we get:
6x + (Water transferred from Tank A to Tank B) = 70
x + (Water transferred from Tank A to Tank B) = 70
Subtracting these equations, we get:
5x = (Water transferred from Tank A to Tank B)
Therefore,
Water transferred from Tank A to Tank B = 5x litres
But, we know that each tank should contain 70 litres of water.
So,
x + (Water transferred from Tank A to Tank B) = 70
x + 5x = 70
6x = 70
x = 11.67
Therefore,
Water transferred from Tank A to Tank B = 5x = 5 × 11.67 = 58.33
Rounding off to the nearest integer, we get:
Water transferred from Tank A to Tank B = 58 litres
Hence, option A (50 litres) is the closest possible answer.
Tank A contains 6 times as much water as Tank B. How much water must M...
7x=140
x=20x6=120
70-20=50
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