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In the Balmer series, the wavelength of the first line is ‘λ1’, and in the Brackett series wavelength of the first line is ‘λ2’ then λ1/λ2 isa)0.162b)0.124c)0.138d)0.188Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the Balmer series, the wavelength of the first line is ‘λ1’, and in the Brackett series wavelength of the first line is ‘λ2’ then λ1/λ2 isa)0.162b)0.124c)0.138d)0.188Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the Balmer series, the wavelength of the first line is ‘λ1’, and in the Brackett series wavelength of the first line is ‘λ2’ then λ1/λ2 isa)0.162b)0.124c)0.138d)0.188Correct answer is option 'A'. Can you explain this answer?.

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Here you can find the meaning of In the Balmer series, the wavelength of the first line is ‘λ1’, and in the Brackett series wavelength of the first line is ‘λ2’ then λ1/λ2 isa)0.162b)0.124c)0.138d)0.188Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In the Balmer series, the wavelength of the first line is ‘λ1’, and in the Brackett series wavelength of the first line is ‘λ2’ then λ1/λ2 isa)0.162b)0.124c)0.138d)0.188Correct answer is option 'A'. Can you explain this answer?, a detailed solution for In the Balmer series, the wavelength of the first line is ‘λ1’, and in the Brackett series wavelength of the first line is ‘λ2’ then λ1/λ2 isa)0.162b)0.124c)0.138d)0.188Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of In the Balmer series, the wavelength of the first line is ‘λ1’, and in the Brackett series wavelength of the first line is ‘λ2’ then λ1/λ2 isa)0.162b)0.124c)0.138d)0.188Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In the Balmer series, the wavelength of the first line is ‘λ1’, and in the Brackett series wavelength of the first line is ‘λ2’ then λ1/λ2 isa)0.162b)0.124c)0.138d)0.188Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.