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Find the smallest 5 digit number which is divisible by 21 , 28, 36 , 45?
Most Upvoted Answer
Find the smallest 5 digit number which is divisible by 21 , 28, 36 , 4...
Introduction:
In this problem, we need to find the smallest 5 digit number that is divisible by 21, 28, 36, and 45. To solve this problem, we need to find the LCM (least common multiple) of these numbers.

Method:
To find the LCM of these numbers, we need to follow these steps:
1. Prime factorize all the given numbers.
2. Write down the prime factors with the highest power.
3. Multiply these prime factors to get the LCM.

Solution:
1. Prime factorization of 21:
21 = 3 x 7

2. Prime factorization of 28:
28 = 2^2 x 7

3. Prime factorization of 36:
36 = 2^2 x 3^2

4. Prime factorization of 45:
45 = 3^2 x 5

Writing the prime factors with the highest power:
- 2^2
- 3^2
- 5
- 7

Multiplying the prime factors:
2^2 x 3^2 x 5 x 7 = 1260

Conclusion:
The smallest 5 digit number that is divisible by 21, 28, 36, and 45 is 1260.
Community Answer
Find the smallest 5 digit number which is divisible by 21 , 28, 36 , 4...
1260 x 8 = 10080 which is five digit. Therefore 10080 is the smallest 5 digit number which is exactly divisible by 21, 28, 36, 45.
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Find the smallest 5 digit number which is divisible by 21 , 28, 36 , 45?
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Find the smallest 5 digit number which is divisible by 21 , 28, 36 , 45? for Class 6 2024 is part of Class 6 preparation. The Question and answers have been prepared according to the Class 6 exam syllabus. Information about Find the smallest 5 digit number which is divisible by 21 , 28, 36 , 45? covers all topics & solutions for Class 6 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the smallest 5 digit number which is divisible by 21 , 28, 36 , 45?.
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