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Direction: 75 kg missile is dropped downwards from an air plane, and has a speed of 60 m/s at an altitude of 850 m above the ground. Determine:
(a) The K.E. possessed by the missile at 850 m.
(b) The P.E. possessed by the missile at 850 m.
(c) The total mechanical energy possessed by the missile.
(d) The K.E. and velocity with which it strikes the ground.
Q. The total mechanical energy possessed by the missile.
  • a)
    77250 J
  • b)
    7725000 J
  • c)
    772500 J
  • d)
    775200 J
Correct answer is option 'C'. Can you explain this answer?
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Direction: 75 kg missile is dropped downwards from an air plane, and ...
Total mechanical energy of the missile = K.E. + P.E.
= 135000 + 637500 = 7.7 × 105J = 772500 J.
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Most Upvoted Answer
Direction: 75 kg missile is dropped downwards from an air plane, and ...
To solve this problem, we need to use the formulas for kinetic energy (KE) and potential energy (PE), as well as the concept of mechanical energy.

(a) The kinetic energy possessed by the missile at 850 m can be determined using the formula: KE = 0.5 * m * v^2, where m is the mass of the missile and v is its velocity. Given that the mass of the missile is 75 kg and its velocity is 60 m/s, we can calculate the kinetic energy as follows:

KE = 0.5 * 75 kg * (60 m/s)^2
= 0.5 * 75 kg * 3600 m^2/s^2
= 0.5 * 270000 kg m^2/s^2
= 135000 J

Therefore, the kinetic energy possessed by the missile at 850 m is 135000 J.

(b) The potential energy possessed by the missile at 850 m can be determined using the formula: PE = m * g * h, where m is the mass of the missile, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height above the ground. Given that the mass of the missile is 75 kg and the height above the ground is 850 m, we can calculate the potential energy as follows:

PE = 75 kg * 9.8 m/s^2 * 850 m
= 637500 J

Therefore, the potential energy possessed by the missile at 850 m is 637500 J.

(c) The total mechanical energy possessed by the missile is the sum of its kinetic energy and potential energy at 850 m. Therefore, the total mechanical energy is:

Total mechanical energy = KE + PE
= 135000 J + 637500 J
= 772500 J

Therefore, the total mechanical energy possessed by the missile is 772500 J.

(d) The kinetic energy and velocity with which the missile strikes the ground can be determined using the principle of conservation of mechanical energy. Since there is no change in the potential energy of the missile between 850 m and the ground, the decrease in potential energy is equal to the increase in kinetic energy. Therefore, the kinetic energy with which the missile strikes the ground is 637500 J.

To find the velocity, we can use the equation KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the missile, and v is the velocity. Rearranging the equation, we have:

v^2 = (2 * KE) / m
v^2 = (2 * 637500 J) / 75 kg
v^2 = 17000 m^2/s^2

Taking the square root of both sides, we find:

v = √(17000 m^2/s^2)
≈ 130.39 m/s

Therefore, the kinetic energy and velocity with which the missile strikes the ground are approximately 637500 J and 130.39 m/s, respectively.
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Direction: 75 kg missile is dropped downwards from an air plane, and has a speed of 60 m/s at an altitude of 850 m above the ground. Determine:(a) The K.E. possessed by the missile at 850 m.(b) The P.E. possessed by the missile at 850 m.(c) The total mechanical energy possessed by the missile.(d) The K.E. and velocity with which it strikes the ground.Q. The total mechanical energy possessed by the missile.a)77250 Jb)7725000 Jc)772500 Jd)775200 JCorrect answer is option 'C'. Can you explain this answer?
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Direction: 75 kg missile is dropped downwards from an air plane, and has a speed of 60 m/s at an altitude of 850 m above the ground. Determine:(a) The K.E. possessed by the missile at 850 m.(b) The P.E. possessed by the missile at 850 m.(c) The total mechanical energy possessed by the missile.(d) The K.E. and velocity with which it strikes the ground.Q. The total mechanical energy possessed by the missile.a)77250 Jb)7725000 Jc)772500 Jd)775200 JCorrect answer is option 'C'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Direction: 75 kg missile is dropped downwards from an air plane, and has a speed of 60 m/s at an altitude of 850 m above the ground. Determine:(a) The K.E. possessed by the missile at 850 m.(b) The P.E. possessed by the missile at 850 m.(c) The total mechanical energy possessed by the missile.(d) The K.E. and velocity with which it strikes the ground.Q. The total mechanical energy possessed by the missile.a)77250 Jb)7725000 Jc)772500 Jd)775200 JCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction: 75 kg missile is dropped downwards from an air plane, and has a speed of 60 m/s at an altitude of 850 m above the ground. Determine:(a) The K.E. possessed by the missile at 850 m.(b) The P.E. possessed by the missile at 850 m.(c) The total mechanical energy possessed by the missile.(d) The K.E. and velocity with which it strikes the ground.Q. The total mechanical energy possessed by the missile.a)77250 Jb)7725000 Jc)772500 Jd)775200 JCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Direction: 75 kg missile is dropped downwards from an air plane, and has a speed of 60 m/s at an altitude of 850 m above the ground. Determine:(a) The K.E. possessed by the missile at 850 m.(b) The P.E. possessed by the missile at 850 m.(c) The total mechanical energy possessed by the missile.(d) The K.E. and velocity with which it strikes the ground.Q. The total mechanical energy possessed by the missile.a)77250 Jb)7725000 Jc)772500 Jd)775200 JCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 9. Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free.
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