Class 11 Exam > Class 11 Questions > For nomenclature of alkenes in the IUPAC sys...
Start Learning for Free
For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).
Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.
- a)4σ and 1π
- b)5σ and 2π
- c)4σ and 2π
- d)5σ and 1π
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
For nomenclature of alkenes in the IUPAC system, the longest chain of...
Number of σ bonds = 5
Number of π bond = 1
Most Upvoted Answer
For nomenclature of alkenes in the IUPAC system, the longest chain of...
Explanation:
To determine the number of σ and π-bonds in C2H4 (ethylene/ethene), we need to understand the structure of the molecule and the nature of σ and π-bonds.
Structure of Ethylene:
Ethylene (C2H4) is a hydrocarbon with a double bond between two carbon atoms. It can be represented as follows:
H H
| |
H-C=C-H
| |
H H
Nature of σ and π-bonds:
σ (sigma) bonds are formed by the overlapping of atomic orbitals head-on. They allow rotation around the bond axis. In ethylene, each carbon atom forms three σ-bonds: two σ-bonds with hydrogen atoms and one σ-bond with the other carbon atom.
π (pi) bonds are formed by the sideways overlap of p-orbitals. They do not allow rotation around the bond axis. In ethylene, the double bond is formed by one σ-bond and one π-bond between the two carbon atoms.
Counting σ and π-bonds:
Using the structure of ethylene, we can count the number of σ and π-bonds.
- There are two carbon atoms in ethylene, and each carbon atom forms three σ-bonds with hydrogen atoms (two σ-bonds) and the other carbon atom (one σ-bond). So, the total number of σ-bonds is 2 carbon atoms * 3 σ-bonds = 6 σ-bonds (3 on each carbon atom).
- The double bond between the two carbon atoms consists of one σ-bond and one π-bond. So, the total number of π-bonds is 1 π-bond.
Therefore, the number of σ and π-bonds in C2H4 (ethylene/ethene) is 6σ and 1π, which corresponds to option 'D' (5σ and 1π).
Summary:
- The number of σ-bonds in C2H4 (ethylene/ethene) is 6.
- The number of π-bonds in C2H4 (ethylene/ethene) is 1.
To determine the number of σ and π-bonds in C2H4 (ethylene/ethene), we need to understand the structure of the molecule and the nature of σ and π-bonds.
Structure of Ethylene:
Ethylene (C2H4) is a hydrocarbon with a double bond between two carbon atoms. It can be represented as follows:
H H
| |
H-C=C-H
| |
H H
Nature of σ and π-bonds:
σ (sigma) bonds are formed by the overlapping of atomic orbitals head-on. They allow rotation around the bond axis. In ethylene, each carbon atom forms three σ-bonds: two σ-bonds with hydrogen atoms and one σ-bond with the other carbon atom.
π (pi) bonds are formed by the sideways overlap of p-orbitals. They do not allow rotation around the bond axis. In ethylene, the double bond is formed by one σ-bond and one π-bond between the two carbon atoms.
Counting σ and π-bonds:
Using the structure of ethylene, we can count the number of σ and π-bonds.
- There are two carbon atoms in ethylene, and each carbon atom forms three σ-bonds with hydrogen atoms (two σ-bonds) and the other carbon atom (one σ-bond). So, the total number of σ-bonds is 2 carbon atoms * 3 σ-bonds = 6 σ-bonds (3 on each carbon atom).
- The double bond between the two carbon atoms consists of one σ-bond and one π-bond. So, the total number of π-bonds is 1 π-bond.
Therefore, the number of σ and π-bonds in C2H4 (ethylene/ethene) is 6σ and 1π, which corresponds to option 'D' (5σ and 1π).
Summary:
- The number of σ-bonds in C2H4 (ethylene/ethene) is 6.
- The number of π-bonds in C2H4 (ethylene/ethene) is 1.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Top Courses for Class 11View all
For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer?
Question Description
For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer?.
For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer?.
Solutions for For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice For nomenclature of alkenes in the IUPAC system, the longest chain of carbon atoms containing the double bond is selected. Numbering of the chain is done from the end which is nearer to the double bond. The suffix ‘ene’ replaces ‘ane’ of alkanes. The first member of the alkene series is: CH2 (replacing n by 1 in CnH2n) known as methene but has a very short life. The first stable member of the alkene series is C2H4 known as ethylene (common) or ethene (IUPAC).Q. The number of σ and π-bonds in C2H4 is ............... and ............. respectively.a)4σ and 1πb)5σ and 2πc)4σ and 2πd)5σ and 1πCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup