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In the pulley block system shown assume the friction to be negligible and thus into the light and inextensible the mass of block a b c are 1 kilo 2 kilo 3 kilo respectively?
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In the pulley block system shown assume the friction to be negligible ...
Introduction:
In this problem, we are given a pulley block system consisting of three blocks A, B, and C with masses of 1 kg, 2 kg, and 3 kg respectively. We are asked to determine the tension in the strings and the acceleration of the system assuming negligible friction.

Free Body Diagram:
The first step in solving this problem is to draw a free body diagram of each block. We can assume that the strings are massless and the pulleys are frictionless. The tension in the strings will be the same throughout the system.

Equations of Motion:
Next, we can use Newton's second law to write equations of motion for each block. We can assume that the acceleration of the system is a and that the direction of motion is to the right. The equations of motion for each block are:

For block A: T - m1g = m1a
For block B: T - m2g = m2a
For block C: T - m3g = m3a

System of Equations:
We can solve these equations simultaneously to find the tension in the strings and the acceleration of the system. Adding the equations for blocks A and B, we get:

2T - (m1 + m2)g = (m1 + m2)a

Similarly, adding the equations for blocks B and C, we get:

2T - (m2 + m3)g = (m2 + m3)a

Solution:
Solving these two equations simultaneously for T and a, we get:

T = (m1 + m2 + m3)g / 4 = 24.5 N
a = g / 4 = 2.45 m/s^2

Therefore, the tension in the strings is 24.5 N and the acceleration of the system is 2.45 m/s^2.
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In the pulley block system shown assume the friction to be negligible and thus into the light and inextensible the mass of block a b c are 1 kilo 2 kilo 3 kilo respectively?
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