An inertial frame of reference B is moving along the x-axis with a velocity 9×10^6 m/s with respect to another inertial frame A. A rod is located in the frame A with its two ends at the coordinate points (5,-5,0) B is? Some please explain.?

Question

Answer

Problem: An inertial frame of reference B is moving along the x-axis with a velocity 9×10^6 m/s with respect to another inertial frame A. A rod is located in the frame A with its two ends at the coordinate points (5,-5,0) B is?

Solution:

Understanding the problem: In this problem, we are given two inertial frames of reference A and B. B is moving along the x-axis with respect to A. We are also given the coordinates of a rod in frame A and we need to find its coordinates in frame B.

Converting coordinates from A to B: To convert the coordinates of the rod from frame A to frame B, we need to use the Galilean transformation equations. The coordinates of the rod in frame B can be obtained as follows:
- x' = x - vt
- y' = y
- z' = z
Here, v is the velocity of frame B with respect to frame A along the x-axis, t is the time elapsed and (x,y,z) are the coordinates of the rod in frame A.

Calculating the coordinates in frame B: Using the above equations, we can calculate the coordinates of the rod in frame B as follows:
- x' = 5 - (9×10^6)t
- y' = -5
- z' = 0

Therefore, the coordinates of the rod in frame B are (5 - (9×10^6)t, -5, 0).

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