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A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would be
- a)unchanged
- b)four times the original value
- c)one fourth of the original value
- d)twice the original value
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A metal surface is illuminated by the light of given intensity and fre...
The maximum kinetic energy of photootecirons is given by KEmax = h(v-v0) …(i)
Where, h = Planck's constant,
v = frequency of radiation
and v0 = threshold frequency.
It can be seen from Eq.(i), that the maximum KE of the emitted photoelectron is proportional to the frequency of the radiation and is independent of the intensity of radiation, so it remains unchanged.
Most Upvoted Answer
A metal surface is illuminated by the light of given intensity and fre...
Explanation:
The photoelectric effect is the phenomenon where electrons are emitted from a metal surface when exposed to light of a certain frequency (threshold frequency). The kinetic energy of the emitted electrons depends on the intensity and frequency of the incident light.
Effect of intensity on maximum KE:
- Increasing the intensity of light increases the number of photons incident on the metal surface, which in turn increases the number of emitted electrons.
- However, the maximum kinetic energy of the emitted electrons remains unchanged as it depends only on the frequency of the incident light.
- Therefore, reducing the intensity of light will decrease the number of emitted electrons but will not change their maximum kinetic energy.
Mathematically, the maximum kinetic energy of the emitted electrons can be expressed as:
KEmax = hf - Φ
where h is Planck's constant, f is the frequency of the incident light, and Φ is the work function of the metal (minimum energy required to remove an electron from its surface).
Conclusion:
Therefore, reducing the intensity of illumination to one fourth of its original value will not change the maximum kinetic energy of the emitted photoelectrons. Hence, the correct answer is option 'A'.
The photoelectric effect is the phenomenon where electrons are emitted from a metal surface when exposed to light of a certain frequency (threshold frequency). The kinetic energy of the emitted electrons depends on the intensity and frequency of the incident light.
Effect of intensity on maximum KE:
- Increasing the intensity of light increases the number of photons incident on the metal surface, which in turn increases the number of emitted electrons.
- However, the maximum kinetic energy of the emitted electrons remains unchanged as it depends only on the frequency of the incident light.
- Therefore, reducing the intensity of light will decrease the number of emitted electrons but will not change their maximum kinetic energy.
Mathematically, the maximum kinetic energy of the emitted electrons can be expressed as:
KEmax = hf - Φ
where h is Planck's constant, f is the frequency of the incident light, and Φ is the work function of the metal (minimum energy required to remove an electron from its surface).
Conclusion:
Therefore, reducing the intensity of illumination to one fourth of its original value will not change the maximum kinetic energy of the emitted photoelectrons. Hence, the correct answer is option 'A'.
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A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would bea)unchangedb)four times the original valuec)one fourth of the original valued)twice the original valueCorrect answer is option 'A'. Can you explain this answer?
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A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would bea)unchangedb)four times the original valuec)one fourth of the original valued)twice the original valueCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would bea)unchangedb)four times the original valuec)one fourth of the original valued)twice the original valueCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would bea)unchangedb)four times the original valuec)one fourth of the original valued)twice the original valueCorrect answer is option 'A'. Can you explain this answer?.
A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would bea)unchangedb)four times the original valuec)one fourth of the original valued)twice the original valueCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would bea)unchangedb)four times the original valuec)one fourth of the original valued)twice the original valueCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would bea)unchangedb)four times the original valuec)one fourth of the original valued)twice the original valueCorrect answer is option 'A'. Can you explain this answer?.
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A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would bea)unchangedb)four times the original valuec)one fourth of the original valued)twice the original valueCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would bea)unchangedb)four times the original valuec)one fourth of the original valued)twice the original valueCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A metal surface is illuminated by the light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would bea)unchangedb)four times the original valuec)one fourth of the original valued)twice the original valueCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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