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A block of mass ‘m’ moving on a frictionless surface at speed V collides elastically with a block of the same mass, initially at rest. Now the first block moves at an angle 'θ’ with its Initial direction and has speed ‘v1’. The speed of the second block after the collision is

  • a)

  • b)

  • c)

  • d)

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A block of mass ‘m’ moving on a frictionless surface at sp...
Applying the law of conservation of kinetic energy, KE (before collision) = KE (after collision)






Thus, the velocity of the second block after the collision is
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A block of mass ‘m’ moving on a frictionless surface at speed V collides elastically with a block of the same mass, initially at rest. Now the first block moves at an angle θ’ with its Initial direction and has speed ‘v1’. The speed of the second block after the collision isa)b)c)d)Correct answer is option 'B'. Can you explain this answer?
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