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When the electron in the hydrogen atom jumps from the fourth Bohr orbit to the second Bohr orbit, one gets the
  • a)
    The second line of Balmer series
  • b)
    The first line of Balmer series
  • c)
    The first line of the Pfund series
  • d)
    The second line of the Paschon series
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
When the electron in the hydrogen atom jumps from the fourth Bohr orbi...
The wavelength of line in cased Baimer series is given by where n = 3,4,5 and R = Rydberg constant.
So, for the Balmer series, the transition takes from third orbit to second for first line spectrum, fourth orbit to second for second line spectrum, etc. Hence, the given transition represents the second line of the Balmer series.
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When the electron in the hydrogen atom jumps from the fourth Bohr orbi...
Explanation:
The hydrogen atom has only one electron in its outermost shell, and it can jump from one orbit to another by absorbing or emitting energy. When the electron jumps from a higher energy level to a lower energy level, it releases energy in the form of electromagnetic radiation, which can be detected as a spectral line.

The spectral lines of hydrogen are classified into different series, depending on the final energy level of the electron. The four main series are named after their discoverers: the Lyman series, Balmer series, Paschen series, and Brackett series. Each series corresponds to a different range of final energy levels, and the lines within each series have different wavelengths and frequencies.

In this question, the electron in the hydrogen atom is jumping from the fourth Bohr orbit to the second Bohr orbit. This corresponds to a transition from a higher energy level to a lower energy level, so energy is released in the form of electromagnetic radiation.

The correct answer is option A, which states that this transition produces the second line of the Balmer series. The Balmer series corresponds to transitions where the final energy level is the second shell (n=2) and the initial energy level is higher than that. The second line of the Balmer series corresponds to a transition from the fourth shell (n=4) to the second shell (n=2), which is exactly what is happening in this question.

Therefore, the correct answer is A, the second line of the Balmer series.
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Can you explain the answer of this question below:The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively. Maximum number of lines produced when an electron jumps from nth level to ground level is equal to . For examle, in the case of n = 4, number of lines produced is 6. (4 3, 4 2, 4 1, 3 2, 3 1, 2 1). When an electron returns from n2 to n1 state, the number of lines in the spectrum will be equal toIf the electron comes back from energy level having energy E2 to energy level having energy E1, then the difference may be expressed in terms of energy of photon as :Since h and c are constants, E corresponds to definite energy; thus each transition from one energy level to another will produce a light of definite wavelength. This is actually observed as a line in the spectrum of hydrogen atom.Wave number of line is given by the formulawhere R is a Rydbergs constant(R = 1.1 107 m-1)Q.The energy photon emitted corresponding to transition n = 3 to n = 1 is [h = 6 10-34 J - sec]A:1.76 10-18 JB:1.98 10-18 JC:1.76 10-17 JD:None of theseThe answer is a.

The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively. Maximum number of lines produced when an electron jumps from nth level to ground level is equal to . For examle, in the case of n = 4, number of lines produced is 6. (4 3, 4 2, 4 1, 3 2, 3 1, 2 1). When an electron returns from n2 to n1 state, the number of lines in the spectrum will be equal toIf the electron comes back from energy level having energy E2 to energy level having energy E1, then the difference may be expressed in terms of energy of photon as :Since h and c are constants, E corresponds to definite energy; thus each transition from one energy level to another will produce a light of definite wavelength. This is actually observed as a line in the spectrum of hydrogen atom.Wave number of line is given by the formulawhere R is a Rydbergs constant(R = 1.1 107 m-1)Q.The difference in the wavelength of the 1st line of Lyman series and 2nd line of Balmer series in a hydrogen atom is

The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively. Maximum number of lines produced when an electron jumps from nth level to ground level is equal to . For examle, in the case of n = 4, number of lines produced is 6. (4 3, 4 2, 4 1, 3 2, 3 1, 2 1). When an electron returns from n2 to n1 state, the number of lines in the spectrum will be equal toIf the electron comes back from energy level having energy E2 to energy level having energy E1, then the difference may be expressed in terms of energy of photon as :Since h and c are constants, E corresponds to definite energy; thus each transition from one energy level to another will produce a light of definite wavelength. This is actually observed as a line in the spectrum of hydrogen atom.Wave number of line is given by the formulawhere R is a Rydbergs constant(R = 1.1 107 m-1)Q.In a collection of Hatom, electrons make transition from 5th excited state to 2nd excited state then maximum number of different types of photons observed are

The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively. Maximum number of lines produced when an electron jumps from nth level to ground level is equal to . For examle, in the case of n = 4, number of lines produced is 6. (4 3, 4 2, 4 1, 3 2, 3 1, 2 1). When an electron returns from n2 to n1 state, the number of lines in the spectrum will be equal toIf the electron comes back from energy level having energy E2 to energy level having energy E1, then the difference may be expressed in terms of energy of photon as :Since h and c are constants, E corresponds to definite energy; thus each transition from one energy level to another will produce a light of definite wavelength. This is actually observed as a line in the spectrum of hydrogen atom.Wave number of line is given by the formulawhere R is a Rydbergs constant(R = 1.1 107 m-1)Q.The wave number of electromagnetic radiation emitted during the transition of electron in between two levels of Li2+ ion whose principal quantum numbers sum is 4 and difference is 2 is

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When the electron in the hydrogen atom jumps from the fourth Bohr orbit to the second Bohr orbit, one gets thea)The second line of Balmer seriesb)The first line of Balmer seriesc)The first line of the Pfund seriesd)The second line of the Paschon seriesCorrect answer is option 'A'. Can you explain this answer?
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When the electron in the hydrogen atom jumps from the fourth Bohr orbit to the second Bohr orbit, one gets thea)The second line of Balmer seriesb)The first line of Balmer seriesc)The first line of the Pfund seriesd)The second line of the Paschon seriesCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When the electron in the hydrogen atom jumps from the fourth Bohr orbit to the second Bohr orbit, one gets thea)The second line of Balmer seriesb)The first line of Balmer seriesc)The first line of the Pfund seriesd)The second line of the Paschon seriesCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When the electron in the hydrogen atom jumps from the fourth Bohr orbit to the second Bohr orbit, one gets thea)The second line of Balmer seriesb)The first line of Balmer seriesc)The first line of the Pfund seriesd)The second line of the Paschon seriesCorrect answer is option 'A'. Can you explain this answer?.
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