The ratio of the dimensions of Planck’s constant to of the momen...
The dimensions of Planck’s constant,
and that moment of inertia. [l] = [M][R]2 = [M][L]2 = [ML2T0]
∴
Thus, the ratio of dimensions of Planck’s constant to that at the moment of inertia is the dimensions of frequency.
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The ratio of the dimensions of Planck’s constant to of the momen...
Explanation:
Ratio of Planck's constant to dial of moment of inertia can be written as:
[ h / (I x d^2) ]
where h is Planck's constant, I is moment of inertia and d is the diameter of the dial.
The dimensions of Planck's constant are given by [M L^2 T^-1], while the dimensions of the product of moment of inertia and diameter squared are [M L^2].
Therefore, the ratio of the two is:
[M L^2 T^-1] / [M L^2] = [T^-1]
Hence, the dimensions of the ratio is time^-1 or frequency. Therefore, option C is the correct answer.
The ratio of the dimensions of Planck’s constant to of the momen...
Explanation:
Planck’s constant and moment of inertia are both physical quantities with different dimensions. The ratio of their dimensions gives us the dimension of a new physical quantity.
The dimensions of Planck’s constant are [energy][time], while the dimensions of moment of inertia are [mass][length]^2. Therefore, their ratio is:
[h]/[I] = ([energy][time])/([mass][length]^2)
Simplifying this expression, we get:
[h]/[I] = [energy]/([mass][length]^2][time]
The dimension of [energy]/[time] is frequency, and the dimension of [mass][length]^2 is moment of inertia. Therefore, we can conclude that the dimension of [h]/[I] is frequency.
Answer: C) frequency
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