15 ml of oxide of Nitrogen was taken in eudiometry tube and mixed with...
Solution:
Given,
Volume of oxide of nitrogen taken = 15 ml
Volume of hydrogen added = 42 ml
Volume of resulting mixture after sparking = 27 ml
Volume of oxygen added = 10 ml
Volume of resulting mixture after second explosion = 19 ml
Let's assume the formula of the oxide of nitrogen to be NxOy.
Step 1: Determination of the volume of nitrogen present in the oxide of nitrogen
From the given data,
Volume of nitrogen in the oxide of nitrogen = Volume of oxide of nitrogen - Volume of oxygen added
= 15 - 10
= 5 ml
Step 2: Determination of the volume of oxygen present in the oxide of nitrogen
From the given data,
Volume of resulting mixture after sparking = Volume of nitrogen + Volume of hydrogen
= 5 ml + 42 ml
= 47 ml
Let the volume of oxygen in the oxide be x ml.
Then, the volume of nitrogen in the oxide will be (5 - x) ml.
From the equation of reaction,
NxOy + (2y)H2 → N2 + (2y)H2O
The volume of nitrogen released after the explosion = volume of nitrogen in oxide = (5 - x) ml
The volume of hydrogen consumed after the explosion = (2y) x 2 = 4y ml
The volume of water vapour formed after the explosion = (2y) x 2 = 4y ml
So, the volume of nitrogen and water vapour formed after the explosion = 5 ml - 27 ml = -22 ml
Therefore, we have the equation: (5 - x) ml + 4y ml = -22 ml
Step 3: Determination of the volume of oxygen present in the oxide of nitrogen after the second explosion
From the given data,
Volume of resulting mixture after second explosion = Volume of nitrogen + Volume of hydrogen + Volume of oxygen
= (5 - x) ml + 4y ml + 10 ml
= (5 - x + 4y + 10) ml
= (15 - x + 4y) ml
From the equation of reaction,
NxOy + (2x)O2 → 2NOx
The volume of oxygen consumed after the explosion = (2x) x 2 = 4x ml
The volume of nitrogen oxide formed after the explosion = 2(5 - x) ml = 10 - 2x ml
The volume of the mixture after the explosion = 19 ml
Therefore, we have the equation: 4x ml + (10 - 2x) ml = 19 ml
Solving the two equations, we get:
x = 3 and y = 2
Therefore, the formula of the oxide of nitrogen is N2O3.
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