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Fig. (IV.6) shows a slotted lever mechanism where crank OA rotates at 120 rpm in anticlockwise direction about the fixed center O swinging the lever PEQ about the fixed centre E. Find the angular velocity and angular acceleration of link PEQ.OA = 75 mm, BC = 180 mm, QE = 125 mm, BE = 100 mm?
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Fig. (IV.6) shows a slotted lever mechanism where crank OA rotates at ...
Introduction
To analyze the slotted lever mechanism, we will determine the angular velocity and angular acceleration of link PEQ as crank OA rotates at 120 RPM.

Given Data
- Crank OA: 75 mm
- Crank BC: 180 mm
- Link QE: 125 mm
- Link BE: 100 mm
- Speed of crank OA: 120 RPM (anticlockwise)

Angular Velocity of Link PEQ
- The angular velocity (ω) of crank OA can be calculated using the formula:
  • ω_OA = (120 RPM * 2π rad) / 60 s = 12.57 rad/s


- As crank OA rotates, it causes link PEQ to swing. The angular velocity of link PEQ (ω_PEQ) can be derived using the relationship between the velocities in the mechanism:
  • ω_PEQ = (OA / QE) * ω_OA
  • ω_PEQ = (75 mm / 125 mm) * 12.57 rad/s = 7.54 rad/s



Angular Acceleration of Link PEQ
- The angular acceleration (α) of crank OA, assuming it rotates uniformly, is zero:
  • α_OA = 0 rad/s²


- The angular acceleration of link PEQ (α_PEQ) can be found using the relationship between the accelerations:
  • α_PEQ = (OA / QE) * α_OA
  • α_PEQ = (75 mm / 125 mm) * 0 rad/s² = 0 rad/s²



Conclusion
In summary, the angular velocity of link PEQ is 7.54 rad/s, while the angular acceleration is 0 rad/s², indicating that the link swings uniformly as crank OA rotates.
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Fig. (IV.6) shows a slotted lever mechanism where crank OA rotates at 120 rpm in anticlockwise direction about the fixed center O swinging the lever PEQ about the fixed centre E. Find the angular velocity and angular acceleration of link PEQ.OA = 75 mm, BC = 180 mm, QE = 125 mm, BE = 100 mm?
Question Description
Fig. (IV.6) shows a slotted lever mechanism where crank OA rotates at 120 rpm in anticlockwise direction about the fixed center O swinging the lever PEQ about the fixed centre E. Find the angular velocity and angular acceleration of link PEQ.OA = 75 mm, BC = 180 mm, QE = 125 mm, BE = 100 mm? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Fig. (IV.6) shows a slotted lever mechanism where crank OA rotates at 120 rpm in anticlockwise direction about the fixed center O swinging the lever PEQ about the fixed centre E. Find the angular velocity and angular acceleration of link PEQ.OA = 75 mm, BC = 180 mm, QE = 125 mm, BE = 100 mm? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Fig. (IV.6) shows a slotted lever mechanism where crank OA rotates at 120 rpm in anticlockwise direction about the fixed center O swinging the lever PEQ about the fixed centre E. Find the angular velocity and angular acceleration of link PEQ.OA = 75 mm, BC = 180 mm, QE = 125 mm, BE = 100 mm?.
Solutions for Fig. (IV.6) shows a slotted lever mechanism where crank OA rotates at 120 rpm in anticlockwise direction about the fixed center O swinging the lever PEQ about the fixed centre E. Find the angular velocity and angular acceleration of link PEQ.OA = 75 mm, BC = 180 mm, QE = 125 mm, BE = 100 mm? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
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