A hydraulic press exerts a total load of 3.5mega Newton this load is c...
Solution:
Given:
Total load = 3.5 Mega Newton
Safe stress = 85 Mega Pascal
Young's modulus = 210 Kilo Newton / mm^2
Length of each rod = 2.5 meters
Calculation:
Let the diameter of each rod be 'd'
Cross-sectional area of each rod = (π/4) * d^2
Load carried by each rod = Total load / 2 = 1.75 Mega Newton
Stress induced in each rod = Load carried by each rod / Cross-sectional area of each rod
Stress induced in each rod = (Load carried by each rod) / ((π/4) * d^2)
Stress induced in each rod = 1.75 * 10^6 / ((π/4) * d^2)
Safe stress = 85 Mega Pascal
Hence, 1.75 * 10^6 / ((π/4) * d^2) <= 85="" *="" 10^6="">=>
d^2 >= (1.75 * 10^6) / ((π/4) * 85 * 10^6)
d^2 >= 0.00206
d >= √0.00206
d >= 0.0454 meters
Extension in each rod = (Load carried by each rod * Length of each rod) / (Cross-sectional area of each rod * Young's modulus)
Extension in each rod = (1.75 * 10^6 * 2.5) / ((π/4) * (0.0454)^2 * 210 * 10^3)
Extension in each rod = 0.0045 meters
Answer:
Diameter of each rod = 0.0454 meters
Extension of each rod = 0.0045 meters