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If √1 x^2 √1 y^2=a(x-y) then dy/dx=?
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If √1 x^2 √1 y^2=a(x-y) then dy/dx=?
Given Equation: √1 x^2 √1 y^2 = a(x-y)

Step 1: Simplify the equation
- √1 x^2 √1 y^2 = a(x-y)
- x|y| = a(x-y)

Step 2: Differentiate with respect to x
- Differentiating both sides with respect to x:
- d/dx (x|y|) = d/dx (a(x-y))
- |y| + x(d|y|/dx) = a(1 - dy/dx)

Step 3: Solve for dy/dx
- Group the terms involving dy/dx:
- dy/dx = (|y| - a)/(x - a)
Therefore, dy/dx = (|y| - a)/(x - a) is the derivative of y with respect to x in the given equation √1 x^2 √1 y^2 = a(x-y).
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If √1 x^2 √1 y^2=a(x-y) then dy/dx=?
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