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The horizontal component of earth’s magnetic field at a place is 3 times the vertical component. The angle of dip at that place is:
  • a)
    π/6
  • b)
    π/3
  • c)
    π/4
  • d)
    0
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The horizontal component of earth’s magnetic field at a place is...
Target law, BV = BH tanδ
tanδ = BV / BH
Given BH = √3BV
tanδ = BV / √3BV = 1/√3
δ = 30° or π / 6 radians.
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The horizontal component of earth’s magnetic field at a place is 3 times the vertical component. The angle of dip at that place is:a)π/6b)π/3c)π/4d)0Correct answer is option 'A'. Can you explain this answer?
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