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Two bar magnets of the same mass, same length and same breadth have magnetic moments M and 3M, respectively, are joined together pole for pole and suspended by string. The time period of assembly is 3 seconds. Now, polarity of one magnet is reversed and combination is again forced to oscillate in magnetic field, the time of oscillation is
  • a)
    3
  • b)
    2
  • c)
    2√2
  • d)
    3√2
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Two bar magnets of the same mass, same length and same breadth have ma...

⇒ T2 = √2T1 = 3√2
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Two bar magnets of the same mass, same length and same breadth have ma...
The time period of an oscillating magnet in a magnetic field is given by the equation:

T = 2π√(I / M)

where T is the time period, I is the moment of inertia, and M is the magnetic moment.

When the two magnets are joined together pole for pole, the resulting magnetic moment of the combined system is M + 3M = 4M.

The moment of inertia of the combined system can be calculated using the parallel axis theorem:

I = I1 + I2

where I1 and I2 are the moments of inertia of the individual magnets.

Since the two magnets have the same mass, length, and breadth, their moments of inertia will be equal:

I1 = I2 = (1/12) * m * (l^2 + b^2)

where m is the mass of each magnet, l is the length of each magnet, and b is the breadth of each magnet.

Therefore, I = 2 * I1 = 2 * I2 = (1/6) * m * (l^2 + b^2)

Substituting the values of the magnetic moment and moment of inertia into the time period equation, we get:

T = 2π√((1/6) * m * (l^2 + b^2) / (4M))

Simplifying, we get:

T = π√((1/24) * m * (l^2 + b^2) / M)

When the polarity of one magnet is reversed, the resulting magnetic moment of the combined system is 3M - M = 2M.

Using the same calculations as before, the new time period is:

T' = π√((1/24) * m * (l^2 + b^2) / (2M))

Comparing T and T', we can see that T' is equal to T/√2, which means the time period of oscillation is halved.

Therefore, the correct answer is:
c) 2
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Two bar magnets of the same mass, same length and same breadth have magnetic moments M and 3M, respectively, are joined together pole for pole and suspended by string. The time period of assembly is 3 seconds. Now, polarity of one magnet is reversed and combination is again forced to oscillate in magnetic field, the time of oscillation isa)3b)2c)2√2d)3√2Correct answer is option 'D'. Can you explain this answer?
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