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A wind with speed 80 m/s blows parallel to the roof of a house. The area on the roof is 500 m^2. The force exerted by the wind on the roof is (take pressure inside the house as atmospheric pressure and density of air is 1.2 kg/m^3)?
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A wind with speed 80 m/s blows parallel to the roof of a house. The ar...
Calculation of Force Exerted by Wind on the Roof
Given:
- Wind speed: 80 m/s
- Area of the roof: 500 m^2
- Pressure inside the house: Atmospheric pressure
- Density of air: 1.2 kg/m^3
Step 1: Calculate Dynamic Pressure
The dynamic pressure is given by the formula:
Dynamic Pressure = 0.5 * Density * Velocity^2
Given:
Density of air (ρ) = 1.2 kg/m^3
Wind speed (V) = 80 m/s
Substituting the values into the formula:
Dynamic Pressure = 0.5 * 1.2 * 80^2 = 3840 Pa
Step 2: Calculate the Force on the Roof
The force exerted by the wind on the roof is equal to the product of the dynamic pressure and the area of the roof.
Given:
Area of the roof (A) = 500 m^2
Dynamic Pressure (P) = 3840 Pa
Force on the Roof = Dynamic Pressure * Area of the Roof
Substituting the values into the formula:
Force on the Roof = 3840 * 500 = 1,920,000 N
Explanation:
- The force exerted by the wind on the roof is calculated using the dynamic pressure and the area of the roof.
- Dynamic pressure is a measure of the impact of the moving air on a surface.
- The formula for dynamic pressure takes into account the density of air and the square of the wind speed.
- By multiplying the dynamic pressure by the area of the roof, we can determine the force exerted by the wind.
- In this case, the wind speed is given as 80 m/s and the area of the roof is 500 m^2.
- The pressure inside the house is assumed to be the same as atmospheric pressure.
- The density of air is provided as 1.2 kg/m^3.
- After calculating the dynamic pressure and multiplying it by the roof area, we find that the force exerted by the wind on the roof is 1,920,000 N.
Given:
- Wind speed: 80 m/s
- Area of the roof: 500 m^2
- Pressure inside the house: Atmospheric pressure
- Density of air: 1.2 kg/m^3
Step 1: Calculate Dynamic Pressure
The dynamic pressure is given by the formula:
Dynamic Pressure = 0.5 * Density * Velocity^2
Given:
Density of air (ρ) = 1.2 kg/m^3
Wind speed (V) = 80 m/s
Substituting the values into the formula:
Dynamic Pressure = 0.5 * 1.2 * 80^2 = 3840 Pa
Step 2: Calculate the Force on the Roof
The force exerted by the wind on the roof is equal to the product of the dynamic pressure and the area of the roof.
Given:
Area of the roof (A) = 500 m^2
Dynamic Pressure (P) = 3840 Pa
Force on the Roof = Dynamic Pressure * Area of the Roof
Substituting the values into the formula:
Force on the Roof = 3840 * 500 = 1,920,000 N
Explanation:
- The force exerted by the wind on the roof is calculated using the dynamic pressure and the area of the roof.
- Dynamic pressure is a measure of the impact of the moving air on a surface.
- The formula for dynamic pressure takes into account the density of air and the square of the wind speed.
- By multiplying the dynamic pressure by the area of the roof, we can determine the force exerted by the wind.
- In this case, the wind speed is given as 80 m/s and the area of the roof is 500 m^2.
- The pressure inside the house is assumed to be the same as atmospheric pressure.
- The density of air is provided as 1.2 kg/m^3.
- After calculating the dynamic pressure and multiplying it by the roof area, we find that the force exerted by the wind on the roof is 1,920,000 N.
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A wind with speed 80 m/s blows parallel to the roof of a house. The area on the roof is 500 m^2. The force exerted by the wind on the roof is (take pressure inside the house as atmospheric pressure and density of air is 1.2 kg/m^3)?
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A wind with speed 80 m/s blows parallel to the roof of a house. The area on the roof is 500 m^2. The force exerted by the wind on the roof is (take pressure inside the house as atmospheric pressure and density of air is 1.2 kg/m^3)? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A wind with speed 80 m/s blows parallel to the roof of a house. The area on the roof is 500 m^2. The force exerted by the wind on the roof is (take pressure inside the house as atmospheric pressure and density of air is 1.2 kg/m^3)? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wind with speed 80 m/s blows parallel to the roof of a house. The area on the roof is 500 m^2. The force exerted by the wind on the roof is (take pressure inside the house as atmospheric pressure and density of air is 1.2 kg/m^3)?.
A wind with speed 80 m/s blows parallel to the roof of a house. The area on the roof is 500 m^2. The force exerted by the wind on the roof is (take pressure inside the house as atmospheric pressure and density of air is 1.2 kg/m^3)? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A wind with speed 80 m/s blows parallel to the roof of a house. The area on the roof is 500 m^2. The force exerted by the wind on the roof is (take pressure inside the house as atmospheric pressure and density of air is 1.2 kg/m^3)? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wind with speed 80 m/s blows parallel to the roof of a house. The area on the roof is 500 m^2. The force exerted by the wind on the roof is (take pressure inside the house as atmospheric pressure and density of air is 1.2 kg/m^3)?.
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