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Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.?
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Answer:Part of the Eye with Densely Packed Cones - FoveaExplanation:The human eye is a complex organ that works in a coordinated manner. It consists of several parts, each with its unique function. The cones are photoreceptor cells present in the retina of the eye that are responsible for color vision and visual acuity. The part of the eye where cones are densely packed within the right eye is the fovea.Fovea:The fovea is a small, central, and specialized area of the retina located in the macula lutea. It is a depression or pit in the retina measuring about 1.5 mm in diameter and 0.3 mm in depth. The fovea is responsible for central vision, which is the ability to see fine details and distinguish colors. It contains a high density of cones, which are responsible for color vision and visual acuity.Other Parts of the Eye:Sclerotic Coat:The sclerotic coat is the outermost layer of the eye, also known as the white of the eye. It is a tough, fibrous, and protective layer that maintains the shape of the eye.Choroid Coat:The choroid coat is a vascular layer located between the sclera and the retina. It supplies oxygen and nutrients to the retina and absorbs excess light to prevent glare.Lens:The lens is a transparent, biconvex structure located behind the iris. It helps to focus light onto the retina and adjust the focus for near and far objects.Conclusion:In conclusion, the part of the eye with densely packed cones within the right eye is the fovea. It is responsible for central vision and contains a high density of cones that are responsible for color vision and visual acuity. The other parts of the eye include the sclerotic coat, choroid coat, and lens.

Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.?
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Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.? for Teaching 2024 is part of Teaching preparation. The Question and answers have been prepared according to the Teaching exam syllabus. Information about Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.? covers all topics & solutions for Teaching 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.?.
Solutions for Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.? in English & in Hindi are available as part of our courses for Teaching. Download more important topics, notes, lectures and mock test series for Teaching Exam by signing up for free.
Here you can find the meaning of Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.? defined & explained in the simplest way possible. Besides giving the explanation of Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.?, a detailed solution for Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.? has been provided alongside types of Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.? theory, EduRev gives you an ample number of questions to practice Also OS = r and TS = 3 cm ∴ OT = OS - TS = (r - 3) cm Now, in right ΔOTP, we have, OP2 = PT2 OT2 ⇒ r2 = 62 (r - 3)2 ⇒ r2 = 36 r2 9 - 6r ⇒ 6r = 45 ⇒ r =(45/6) = (15/2) = 7.5 cm Thus, the radius of the circle is 7.5 cm.? tests, examples and also practice Teaching tests.
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