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A plastic pipe (k = 0.5 w/mK) carries a fluid such that the convective heat transfer coefficient is 300 w/m2k. Average fluid temperature is 100 ˚C. Inner and outer diameter of the pipe is 3 cm and 4 cm respectively. Heat transfer rate per unit pipe length is 500 w/m. The overall heat transfer coefficient based on outside will be given by?
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A plastic pipe (k = 0.5 w/mK) carries a fluid such that the convective...


Overall Heat Transfer Coefficient Calculation:

  • Step 1: Calculate the thermal resistance of the pipe
  • The thermal resistance of the pipe can be calculated using the formula:
    R_pipe = ln(r2/r1) / (2πkL)
  • Where r1 and r2 are the inner and outer radii of the pipe, k is the thermal conductivity, and L is the length of the pipe.
  • Step 2: Calculate the convective resistance
  • The convective resistance can be calculated as:
    R_convective = 1 / (hA)
  • Where h is the convective heat transfer coefficient and A is the surface area of the pipe.
  • Step 3: Calculate the overall heat transfer coefficient
  • The overall heat transfer coefficient can be calculated as:
    U = 1 / (R_pipe + R_convective)


Calculation:

  • Inner radius (r1) = 0.03 m
  • Outer radius (r2) = 0.04 m
  • Length of the pipe (L) = 1 m
  • Convective heat transfer coefficient (h) = 300 W/m^2K
  • Thermal conductivity (k) = 0.5 W/mK
  • Heat transfer rate per unit pipe length = 500 W/m
  • Calculate the thermal resistance of the pipe: R_pipe = ln(0.04/0.03) / (2π*0.5*1) = 0.021 K/W
  • Calculate the convective resistance: R_convective = 1 / (300*2π*0.04*1) = 0.013 K/W
  • Calculate the overall heat transfer coefficient: U = 1 / (0.021 + 0.013) = 33.33 W/m^2K


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A plastic pipe (k = 0.5 w/mK) carries a fluid such that the convective heat transfer coefficient is 300 w/m2k. Average fluid temperature is 100 ˚C. Inner and outer diameter of the pipe is 3 cm and 4 cm respectively. Heat transfer rate per unit pipe length is 500 w/m. The overall heat transfer coefficient based on outside will be given by?
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